Question

Can someone please help me with these last 5 problems? Ive been working on this all day.

Answer 1

Solve using appropriate substitution.

(x^2 -6x)^2 -11(x^2 -6x) -30=0

Answer 2

Im at the end where I factor for the second time

Answer 3

x^2 -6x-5=0 x^2 -6x-6=0

Answer 4

(x-1)(x-5)=0

I cant seem to factor the second one.. I dont get why

Answer 5

Have you met the "Discriminant"?

\((-6)^{2} - 4(1)(-5) = 36 + 20 = 56\)

56 is not a perfect square. You will not be able to factor it. Your factorization is not correct.

\((-6)^{2} - 4(1)(-6) = 36 + 24 = 60\)

60 is not a perfect square. You will not be able to factor it.

Answer 6

????

Answer 7

Where are you getting all that from?

Answer 8

@freckles

Answer 9

You didn't answer my first question. If you have not met the "Discriminant", that will not make much sense.

Anyway, (x-1)(x-5) = x^2 - 6x + 5 -- The sign on the constant term is not correct as you have it factored.

Have you encountered ANY situation where things cannot be factored? There are other ways to proceed when factoring fails.

Answer 10

I have in the last section the other day..

Answer 11

Yes but all my previous examples and help from people have only factored so I didnt think I was allowed to do a different way

Answer 12

Well, we're stuck on these. They can't be factored. I hope the assignment was not meant just to frustrate you. It's time to pull out the Quadratic Formula or "Completing the Square" or anything else you have in your experience.

Answer 13

Okay

Answer 14

3+- square root 15

Answer 15

3+- square root 14

Answer 16

My answers are wrong.

Answer 17

@IrishBoy123

Answer 18

Since you haven't told us what the question is, it's pretty tough to help you with that. You also haven't shown your work.