Solve log 2x^2 + 2 = 6. Round to the nearest thousandth if necessary.
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OpenStudy (anonymous):
I though i'd reopen a new one. Was afk for a long time
Nnesha (nnesha):
so parentheses isn't there ? right ?
Nnesha (nnesha):
you can tag me 'n the last post :=)
OpenStudy (anonymous):
nope no parenthesis look just like this
\[2x^2 + 2 =6\]
Nnesha (nnesha):
alright so you work is correct!
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Nnesha (nnesha):
ur*
Nnesha (nnesha):
\(\color{blue}{\text{Originally Posted by}}\) @lostinprague
I subtract 2 from both sides
log10 (2x^2) + 2 -2 = 6-2
log10 (2x^2)=4
I then used a = logb (b^a)
so... 4= log10 (10^4)
log10 (2x^2) = log10 (10^4)
then all this other stuff/ not sure I want to type it all out lol
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (anonymous):
okay so it was 50squareroot 2 or 70.711 then? I think thats what I had down
OpenStudy (anonymous):
yeah thats my work
OpenStudy (anonymous):
thanks for helping me :)
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