This is the excercise: (363 × 1.48)/3.5-1.79 + 6.1 × 10^−1 However, my question is unralated the answer. Does 10^-1 out as a significant figure? and if it does, it would count as 1 digit, right?
hmmm what's the question again?
Write 10^{-1} as a decimal, then it should be obvious to you.
\[(\frac{ (363*1.48) }{ 3.5-1.79 })+6.1*10^{-1}\]
0.1
\(\bf a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad \cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}} \\ \quad \\ % negative exponential denominator a^{{\color{red} n}} \implies \cfrac{1}{a^{-\color{red} n}} \qquad \qquad \cfrac{1}{a^{-\color{red} n}}\implies \cfrac{1}{\frac{1}{a^{\color{red} n}}}\implies a^{{\color{red} n}} \)
so does count as significant, and it is 1 digit
Thanks again
My last question is ames Street, QB 1968-69, led Texas to the National Championship in 1969. His 20 straight victories as a starter are still the best in SWC history. How many significant digits does 20 represent? 1. 1 2. 2 3. impossible to determine 4. 0 5. infinite
I know 20 has 1 digit, but how do i know is not a tricky question and they mean 20.00000 which has infinite digits
I meant 20 has 2 digits
You interpret 20 as 20 not 20.00000
And they're asking for the number of significant digits the number 20 has.
Decimals apply mostly with measurement. 20 in this case is the result of "counting" not "measurement".
Technically, counting is a form of measurement, but you wouldn't use decimals for counting whole numbers.
But if it was a measurement i would've being like 20.000..... right?
no, it was actually infinate
but what you're saying make sense
This is one of those "I believe button" type concepts because logically it doesn't make sense, at least not to me, but apparently, "Exact numbers have an infinite number of significant digits".
I would have picked 1 significant digit which would have been supposedly wrong.
Yeah, i get what you are saying, and it makes perfectly sense. On tuesday I will tell my teacher to explain me more about this. I think it is a tricky question
Thank you so much anyway
have a good weekend
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