Question

Check my answers.. I know one of them is incorrect..

Answer 1

Solve.

4[4- 3/2x] +9=41

[] is absolute value

I got x=8 and -8/3

Answer 2

Find all the real solutions.

6x^2/3 -41x ^1/3 -7=0

I got x= -1/216 and 343

Answer 3

If the first equation is
\[\Large 4\left|4-\frac{3}{2}x\right|+9 = 41\]
I'm getting x = 8 or x = -8/3 also. So both of your answers are correct (assuming I wrote the problem above correctly)

Answer 4

3. Solve the polynomial and zero-product.

98x-49= 2x^3 -x^2

I got x=1/2 and -7 and 7

Answer 5

Yes thats the correct problem

Answer 6

4. Solve rational exponent.

(x-6) ^3/2 =125

I got x=31



5. Solve radical equation.

Square root 2x+11 =x+4

- the square root has 11 under it.

I got -3 +- 3i square root 2

Answer 7

`Find all the real solutions.`
`6x^2/3 -41x ^1/3 -7=0`
`I got x= -1/216 and 343`

I'm getting the same solutions as well

Answer 8

Okay

Answer 9

`3. Solve the polynomial and zero-product.`
`98x-49= 2x^3 -x^2`
`I got x=1/2 and -7 and 7`

all three solutions are correct

Answer 10

#4 is correct but #5 is not correct

Answer 11

Okay... Hmmm where did I mess up :/

Answer 12

x^2 +6x+27=0

Is that part correct??

Answer 13

#5 is this problem right?

\[\Large \sqrt{2x+11} =x+4\]

Answer 14

Yes

Answer 15

Square both sides to get...

\[\Large \sqrt{2x+11} =x+4\]
\[\Large \left(\sqrt{2x+11}\right)^2 =(x+4)^2\]
\[\Large 2x+11 =x^2+8x+16\]

Answer 16

Yep I have that

Answer 17

I see where i messed up I added 11 instead of -11

Answer 18

Then get everything to one side
\[\Large 2x+11 =x^2+8x+16\]
\[\Large 2x+11{\color{red}{-11}} =x^2+8x+16{\color{red}{-11}}\]
\[\Large 2x=x^2+8x+5\]
\[\Large 2x{\color{red}{-2x}}=x^2+8x+5{\color{red}{-2x}}\]
\[\Large 0=x^2+6x+5\]
\[\Large x^2+6x+5=0\]

Answer 19

Yeah have that now

Answer 20

ok great

Answer 21

once you have your possible solutions, check them back in the original equation

Answer 22

x=-1 and x=-5

Answer 23

check each of those possible solutions back in the original equation

Answer 24

only -1 is true

Answer 25

Thank you!

Answer 26

yes -5 is extraneous