An electric field is constant at every point on a square surface that is 0.80 m on a side. This field has a magnitude of 8.1 N/C and is oriented at an angle of 35° with respect to the surface, as the drawing shows. Calculate the electric flux ΦE passing through the surface.

Question

anonymous · Answer

Is this calculus physics or physics with no calculus?

anonymous · Answer

Electric flux=electric field x area x cos(theta)

anonymous · Answer

=8.1 N/C x (0.80m)^2 x cos35

irishboy123 · Answer

you need to show the drawing or explain "oriented at an angle of 35° with respect to the surface" more fully

the relevant angle could be 35 deg or 55 deg.|dw:1440861776328:dw|