Question

What is the standard form of the equation of a circle with its center at (2, -3) and passing through the point (-2, 0)?

Answer 1

standard form equation of circle is \[\huge\rm (x-h)^2+(y-k)^2=r^2\]
where (h,k) is the center
and substitute (x,y) for (-2,10) to find radius

Answer 2

let me know if you din't get it

Answer 3

didn't*

Answer 4

Ya I don't sorry

Answer 5

alright so center point is (2,-3) which is (h,k)
and (x,y) point is (-2,0) so replace (h,k) and x y with their values

Answer 6

\[\huge\rm (\color{ReD}{h},\color{blue}{k}),(\color{reD}{2},\color{blue}{-3})\]
first coordinate is h
2nd one is k

Answer 7

\[\huge\rm (x-h)^2+(y-k)^2=r^2\]
so replace h with 2
and k with -3

Answer 8

(-2, 0) what is x and y in this order pair ?

Answer 9

-3,2

Answer 10

that's the center point
in this order piar (-2,0) which one is x-coordinate or which one is y-coordinate

Answer 11

?

Answer 12

2 is the x

Answer 13

it's -2
and yes now substitute \[\huge\rm (-2-2)^2+(0-(-3))^2=r^2\] solve for r

Answer 14

-7?

Answer 15

nope i didn't get that

Answer 16

solve for r^2 **