Question

Please help me form a quadratic equation

Answer 1

\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\]

Is that a good start?

Answer 2

Looks good, plugin the point \((0, h)\) and find the value of \(a\)

Answer 3

-a

Answer 4

what do you mean?

Answer 5

y= -a (b/2+x) (b/2-x)

Or

y= a (b/2+x) (b/2-x)

Should I do -a or a
I should do -a because it's a negative quadratic

Answer 6

It doesn't matter

Answer 7

\[y=a (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\]

plugin the point \((0, h)\) and find the value of \(a\)

Answer 8

Ok I got
a= 4h/b^2

Shouldn't be a negative value?

Answer 9

so the equation is

\[y=\dfrac{4h}{b^2} (\frac{ b }{ 2 }+x)(\frac{ b }{ 2}-x)\]


simplify if you want to

Answer 10

dang. I learned this last year and already forget how

Answer 11

Ahhhhhhhhh yes

y=(-4h-x^2/b^2)+h

Answer 12

do you mean

y = -(4h/b^2)x^2+h

?

Answer 13

can you help me with my geometry? ;~;

Answer 14

Wait I stuffed up

Answer 15

im really sorry

Answer 16

I expanded the bracket and simplified to

y= h - (4hx^2/b^2)

Answer 17

Thanks!