Question

HELP please :)

A patient requires an IV of 0.9% saline solution, also known as normal saline solution. How much distilled water, to the nearest milliliter, must be added to 100 milliliters of a 6 % saline solution to produce normal saline?

Answer 1

:)

Answer 2

:)

Answer 3

:(

Answer 4

@Rushwr @ganeshie8

Answer 5

wait @TRICIACOLLIN i'm trying to help u

Answer 6

Thanks... :))) go on. i thought i was snobbed. hihi

Answer 7

@Abhisar @aaronq

Answer 8

@chmvijay

Answer 9

x % of a saline solution means that x grams of salts are dissolved in 100 ml of water.

Answer 10

okay but pls solve this problem

Answer 11

Do you know the answer?

Answer 12

sadly no :(

Answer 13

Ok, no probs...just wanted to check.

Answer 14

We can use,

Initial volume \(\times\) Initial concentration = Final volume \(\times\) Final concentration

Answer 15

then

Answer 16

Consider you need to add x ml of water then you can write

\(\sf 0.06\times 100=0.009 \times (100+x)\)

Solve for x

Answer 17

I'll suggest you to cross check it cz my physical chem is rusted ...

Answer 18

is the answer 566.67 ml

Answer 19

yes.. thank you! :)))) to both of you :)))

Answer 20

A quadratic equation with real coefficients and leading coefficient 1, has x = -bi as a root. Write the equation in general form. :))