Question

**Will medal** coulomb's law

On number 2 I used the Pythagorean theorem to find the new distance, which i got .087m, found the force of -27.25N but it says its wrong? what am i doing wrong

Answer 1

Perhaps with the trigonometry function you messed up. Strength of electric field between 3 electrons are often presended with iscoleces triangle format but this one looks like an exception. Give me the precise details as to how you went about it so i can identify the problem.

Answer 2

Give me an update as soon as you are done showing the steps

Answer 3

i converted the distances to meters, then i used the Pythagorean theorem, sqrt(.021^2+.085^2)=r, then i just plugged in the values forcoulombs law and got

Answer 4

-27.25N

Answer 5

@Robert136

Answer 6

i used F=kq1q2/r^2

Answer 7

i think im making a careless mistake but dont know where

Answer 8

k being the constant and r beingi the radius and yes that seems valid

Answer 9

let me investigate further

Answer 10

ill try doing it again too

Answer 11

If the r you used came from the hypotenuse, then you calculated the total force. They only want the horizontal part. You have to resolve the vector into components

Answer 12

Are you sure you used different charges to the last point of precision?

Answer 13

how would i find the x component? would i have to know the angle?

Answer 14

Yes as it appear you only calculated the electric field acting between the two particles, and not the one acting at 2.1cm away from the other. You would first calcualte the hypotenuse to account for the electric force acting between the two and then and the base of the triangle using trigonometry and that would be your answer. Make sure to use the length of the hypotenuse as the original electricl field from which to compute the one acting 2.1 cm away from the first particle.

Answer 15

Make sure to identify the length of the hypotenuse and then use the equation to find the electrical force acting between them, and then from that calculated eletrical force you will use trigonometry to calculate the corresponding force acting on the second longest side of the triangle or base of the triangle. The key is to shoot the formula once you get the length of the hypotenuse in meters and THEN use the trigonometry again.

Answer 16

figured it out, i found the angle from the x and y components by using tan and then used trig to find the force of the x component
Thank You!

Answer 17

the answer is -26

Answer 18

Great!!! My pleasure;)