Question

Medals!!
Simplify 12^3/12^7.

Answer 1

ik

Answer 2

it

Answer 3

?

Answer 4

\[\frac{ 1 }{ a^2 } = a^{-2}~~and~~ a^x \times a^y = a^{x+ y}\]

Answer 5

so how do i do it?

Answer 6

\[\frac{ 1 }{ 12^{7} } = 12^{-7}\]

Answer 7

a^x / a^y =a^(x-y)

Answer 8

\[\frac{12^3}{12^7} = 12^{3-7} = 12^?\]

Answer 9

a=12,x=3,y=7

Answer 10

\[\large 12^{-?} \iff \frac{1}{12^?}\]

Answer 11

4

Answer 12

so it is
\[\frac{ 1 }{ 12^4 } \]
now wht??

Answer 13

remember
\[\frac{ 1 }{ a } = a^{-1}\]

Answer 14

oh so would it be - 1/12^4?

Answer 15

12^4

Answer 16

that would be you answer

Answer 17

nah @yinkim52001

Answer 18

@Spring98 u done???

Answer 19

yah why not?

Answer 20

there's no negative exponents .

Answer 21

@yinkim52001 remember
\[\frac{ 1 }{ a } = a^{-1}\]

Answer 22

You never leave your answers with negative exponents unless it's called for. Therefore \[\frac{1}{12^4} = \frac{1}{12\cdot 12\cdot 12\cdot 12}\] Whatever that is is your answer.

Answer 23

12^4 is the answer right?

Answer 24

No.

Answer 25

no its 1/12^4

Answer 26

i see why its 1/12^4

Answer 27

@Jhannybean its asking to just simplfy it ..... so i think we may just write in exponential form

Answer 28

You can have various simplifications @rishavraj either in positive exponential form, fully expanded form, or even negative exponent form. They would all be correct.

Answer 29

what is the answer then ? 1/12^4?

Answer 30

\[\frac{ 1 }{ 12^{4} }\] thats your answer spring

Answer 31

yup

Answer 32

\[\frac{12^{-3}}{12^7} = 12^{-4} =\frac{1}{12^4} = \frac{1}{20736}\] TRy solving the next one yourself @Spring98

Answer 33

thanks @yinkim52001

Answer 34

No problem