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OpenStudy (welshfella):
x^2 + 64
this is a like the difference of 2 squares except you have to use the imaginary number i
remember that i^2 = -1
so can you fit the i values in here
x^2 + 64 = ( x + ____)( x - ____)
OpenStudy (anonymous):
im not sure sorry
OpenStudy (welshfella):
ok what is the square root of 64?
OpenStudy (anonymous):
8
OpenStudy (welshfella):
ok so expand this and see if it comes back to x^2 + 64
(x + 8i)(x - 8i)
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OpenStudy (anonymous):
it does
OpenStudy (welshfella):
just as in difference of 2 squares the middle terms will cancel out
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OpenStudy (welshfella):
16x^2 + 49
handle it in the same way
OpenStudy (welshfella):
take square root of 16x^2 and 49
OpenStudy (anonymous):
(16x+7)(x+7)?
OpenStudy (welshfella):
No - where are the i's???
OpenStudy (anonymous):
(16x+7i)(x+7i)?
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OpenStudy (welshfella):
and you take Square root of 16x^2
OpenStudy (anonymous):
dunno
OpenStudy (anonymous):
well its 4, but idk what to do with it
OpenStudy (welshfella):
it 4x
4x * 4x = 16x^2
OpenStudy (welshfella):
put 4x in each bracket
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OpenStudy (anonymous):
(4x+7i)(4x+7i)?
OpenStudy (welshfella):
yes
(16x + 7i)(x - 7i) would not come back to 4x^2 + 64 because the 2 terms in ix would not cancel out
OpenStudy (anonymous):
okay i get it
OpenStudy (anonymous):
next ones a bit different
OpenStudy (welshfella):
Oh no thats not quite right Look at your signs - doddnt forget its like difference of 2 squares
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OpenStudy (anonymous):
(16x+7i)(x-7i)?
OpenStudy (welshfella):
NO its 4x !!!
OpenStudy (welshfella):
(4x + 7i)(4x - 7i)
OpenStudy (anonymous):
sorry lol i copy and pasted the wron egquation
OpenStudy (anonymous):
i wanted to copy then change the signs but i copied the wrong one
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OpenStudy (welshfella):
dont know why but i can't copy and paste!
OpenStudy (welshfella):
weird
OpenStudy (anonymous):
Find the product of (x + 9i)^2.
next one
OpenStudy (welshfella):
withe the last 3 you just expand the parentheses in the normal way
(x + 9i)(x + 9i)
first multiply the second bracket by x then multiply it by 9i
= x(x + 9i) + 9i(x + 9i)
= x^2 + 9xi + 9xi + ?
can you do the last bit?
OpenStudy (anonymous):
ummmm
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OpenStudy (welshfella):
9i*9i = ?
OpenStudy (anonymous):
sorry i really tired today
OpenStudy (anonymous):
81i?
OpenStudy (welshfella):
81* i^2
and what is i^2 equal to?
OpenStudy (anonymous):
-1
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OpenStudy (welshfella):
so that is 81 * -1 = -81
x^2 + 9xi + 9xi - 81
now just add the 2 middle like terms
OpenStudy (anonymous):
18xi
OpenStudy (welshfella):
right
giving
x^2 + 18xi - 81
OpenStudy (anonymous):
is that it?
OpenStudy (welshfella):
Yes
the 4 th one is done in exactly the same way
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OpenStudy (anonymous):
can u just set it up (expand it) and ill take from their then you check?
OpenStudy (welshfella):
(x - 2i)(x - 2i)
= x(x - 2i) - 2i(x - 2i)
OpenStudy (anonymous):
x^2-2xi-2xi-2i^2?
OpenStudy (anonymous):
um @welshfella
OpenStudy (welshfella):
right so up until the last term -2i*-2i is not -2i^2
- * - = + and 2*2 = 4
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OpenStudy (anonymous):
x^2-2xi-2xi-4i?
OpenStudy (welshfella):
so -2i * -2i = ?
OpenStudy (anonymous):
4i?
OpenStudy (welshfella):
treat i as if it weer an x or a y
x^x = x^2
i* i = ?
OpenStudy (anonymous):
4i^2
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OpenStudy (welshfella):
* tahs x * x = x^2
OpenStudy (welshfella):
right + 4 i^2 = ?
OpenStudy (anonymous):
what do you mean by equals?
OpenStudy (welshfella):
i^2 = -1
so 4i^2 = ?
OpenStudy (anonymous):
-4
4-?
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OpenStudy (welshfella):
-4
OpenStudy (welshfella):
important to remember i = sqrt(-1) so i^2 = -1
OpenStudy (anonymous):
k
OpenStudy (welshfella):
x^2-2xi-2xi-4
= x^2 - 4xi - 4
OpenStudy (anonymous):
so is that the answer cause it says to find the product
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OpenStudy (welshfella):
yes
the last one is more complicated because the last term in the brackets is (3x + 5i)
so you could do the last part (3x + 5i)^2 first then plug it in later
OpenStudy (welshfella):
you can do this in the same way as the last 2
(3 + 5i)(3 + 5i)
= 3(3 + 5i) + 5i(3 + 5i)
ok try and do that
OpenStudy (anonymous):
9+15i+15i-25
OpenStudy (welshfella):
yea good job
and we can simplify it further to
30i - 16
OpenStudy (anonymous):
is that the answer to the problem?
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OpenStudy (welshfella):
No
we have to plug that in to the expansion
(x + (3+5i)(x + (3+5i)
= x(x + (3+5i) + (3 + 5i)(x + (3+5i)
= x^2 +3x + 5xi + 3x + 9 + 15i + 30i -16
OpenStudy (anonymous):
then simplify?
OpenStudy (welshfella):
yes
OpenStudy (welshfella):
hold on - I'm getting tired to thats wrong
OpenStudy (anonymous):
oookkkaaayy
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