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Mathematics 13 Online
OpenStudy (anonymous):

.

OpenStudy (welshfella):

x^2 + 64 this is a like the difference of 2 squares except you have to use the imaginary number i remember that i^2 = -1 so can you fit the i values in here x^2 + 64 = ( x + ____)( x - ____)

OpenStudy (anonymous):

im not sure sorry

OpenStudy (welshfella):

ok what is the square root of 64?

OpenStudy (anonymous):

8

OpenStudy (welshfella):

ok so expand this and see if it comes back to x^2 + 64 (x + 8i)(x - 8i)

OpenStudy (anonymous):

it does

OpenStudy (welshfella):

just as in difference of 2 squares the middle terms will cancel out

OpenStudy (anonymous):

okayy.... so that is the first one

OpenStudy (anonymous):

?

OpenStudy (welshfella):

(x + 8i)(x - 8i) = x^2 + 8ix - 8ix -64*-1 = x^2 + 64

OpenStudy (welshfella):

16x^2 + 49 handle it in the same way

OpenStudy (welshfella):

take square root of 16x^2 and 49

OpenStudy (anonymous):

(16x+7)(x+7)?

OpenStudy (welshfella):

No - where are the i's???

OpenStudy (anonymous):

(16x+7i)(x+7i)?

OpenStudy (welshfella):

and you take Square root of 16x^2

OpenStudy (anonymous):

dunno

OpenStudy (anonymous):

well its 4, but idk what to do with it

OpenStudy (welshfella):

it 4x 4x * 4x = 16x^2

OpenStudy (welshfella):

put 4x in each bracket

OpenStudy (anonymous):

(4x+7i)(4x+7i)?

OpenStudy (welshfella):

yes (16x + 7i)(x - 7i) would not come back to 4x^2 + 64 because the 2 terms in ix would not cancel out

OpenStudy (anonymous):

okay i get it

OpenStudy (anonymous):

next ones a bit different

OpenStudy (welshfella):

Oh no thats not quite right Look at your signs - doddnt forget its like difference of 2 squares

OpenStudy (anonymous):

(16x+7i)(x-7i)?

OpenStudy (welshfella):

NO its 4x !!!

OpenStudy (welshfella):

(4x + 7i)(4x - 7i)

OpenStudy (anonymous):

sorry lol i copy and pasted the wron egquation

OpenStudy (anonymous):

i wanted to copy then change the signs but i copied the wrong one

OpenStudy (welshfella):

dont know why but i can't copy and paste!

OpenStudy (welshfella):

weird

OpenStudy (anonymous):

Find the product of (x + 9i)^2. next one

OpenStudy (welshfella):

withe the last 3 you just expand the parentheses in the normal way (x + 9i)(x + 9i) first multiply the second bracket by x then multiply it by 9i = x(x + 9i) + 9i(x + 9i) = x^2 + 9xi + 9xi + ? can you do the last bit?

OpenStudy (anonymous):

ummmm

OpenStudy (welshfella):

9i*9i = ?

OpenStudy (anonymous):

sorry i really tired today

OpenStudy (anonymous):

81i?

OpenStudy (welshfella):

81* i^2 and what is i^2 equal to?

OpenStudy (anonymous):

-1

OpenStudy (welshfella):

so that is 81 * -1 = -81 x^2 + 9xi + 9xi - 81 now just add the 2 middle like terms

OpenStudy (anonymous):

18xi

OpenStudy (welshfella):

right giving x^2 + 18xi - 81

OpenStudy (anonymous):

is that it?

OpenStudy (welshfella):

Yes the 4 th one is done in exactly the same way

OpenStudy (anonymous):

can u just set it up (expand it) and ill take from their then you check?

OpenStudy (welshfella):

(x - 2i)(x - 2i) = x(x - 2i) - 2i(x - 2i)

OpenStudy (anonymous):

x^2-2xi-2xi-2i^2?

OpenStudy (anonymous):

um @welshfella

OpenStudy (welshfella):

right so up until the last term -2i*-2i is not -2i^2 - * - = + and 2*2 = 4

OpenStudy (anonymous):

x^2-2xi-2xi-4i?

OpenStudy (welshfella):

so -2i * -2i = ?

OpenStudy (anonymous):

4i?

OpenStudy (welshfella):

treat i as if it weer an x or a y x^x = x^2 i* i = ?

OpenStudy (anonymous):

4i^2

OpenStudy (welshfella):

* tahs x * x = x^2

OpenStudy (welshfella):

right + 4 i^2 = ?

OpenStudy (anonymous):

what do you mean by equals?

OpenStudy (welshfella):

i^2 = -1 so 4i^2 = ?

OpenStudy (anonymous):

-4 4-?

OpenStudy (welshfella):

-4

OpenStudy (welshfella):

important to remember i = sqrt(-1) so i^2 = -1

OpenStudy (anonymous):

k

OpenStudy (welshfella):

x^2-2xi-2xi-4 = x^2 - 4xi - 4

OpenStudy (anonymous):

so is that the answer cause it says to find the product

OpenStudy (welshfella):

yes the last one is more complicated because the last term in the brackets is (3x + 5i) so you could do the last part (3x + 5i)^2 first then plug it in later

OpenStudy (welshfella):

you can do this in the same way as the last 2 (3 + 5i)(3 + 5i) = 3(3 + 5i) + 5i(3 + 5i) ok try and do that

OpenStudy (anonymous):

9+15i+15i-25

OpenStudy (welshfella):

yea good job and we can simplify it further to 30i - 16

OpenStudy (anonymous):

is that the answer to the problem?

OpenStudy (welshfella):

No we have to plug that in to the expansion (x + (3+5i)(x + (3+5i) = x(x + (3+5i) + (3 + 5i)(x + (3+5i) = x^2 +3x + 5xi + 3x + 9 + 15i + 30i -16

OpenStudy (anonymous):

then simplify?

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

hold on - I'm getting tired to thats wrong

OpenStudy (anonymous):

oookkkaaayy

OpenStudy (welshfella):

x(x + (3+5i) + (3 + 5i)(x + (3+5i) = x^2 + 3x + 5xi + 3x + 5xi + 30i - 16

OpenStudy (welshfella):

thats it now simplify that was a tricky one

OpenStudy (anonymous):

x^2+6x+10xi+30i-16

OpenStudy (anonymous):

?

OpenStudy (welshfella):

looks good

OpenStudy (anonymous):

is that iT?

OpenStudy (welshfella):

yea

OpenStudy (anonymous):

Thanks thats it for now

OpenStudy (welshfella):

good I think I'll take a break lol

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