Question

Can someone help me please?

Answer 1

yes

Answer 2

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit.
\[x ^{2} + 2x + y ^{2} + 4y = 20\]

Answer 3

This is what I have so far
x² + 2x + y² + 4y = 20
(x² + 2x) + (y² + 4y) = 20
(x² + 2x+1) + (y² + 4y+4) = 20 + (1 + 4)
(x² + 2x+1) + (y² + 4y+4) = 25

Answer 4

k give me a sec to solve

Answer 5

I have been using this for the steps. I'm on step 4, but I can't quite seem to figure out how to "factor each quadratic".

Answer 6

ok so take the question and type it into mathway (mathway.com) it will give you the answer and the steps

Answer 7

Okay, I will try that. Thanks.

Answer 8

Medal?

Answer 9

you can really go right to the answer without all that rigamarole

Answer 10

\[x ^{2} + 2x + y ^{2} + 4y = 20\] half of 2 is 1, \(6^2=1\)
half of 4 is 2, \(2^2=4\)
go right from there to
\[(x+1)^2+(y+2)^2=20+1+4\]

Answer 11

oops i meant "\(1^2=1\)"

Answer 12

Oh okay, so the center would be (1,2) and the radius would be 5?

Answer 13

no

Answer 14

the radius is 5, that is correct

Answer 15

center is \((-1,-2)\)

Answer 16

Ah gotcha. I get it. Thank you!

Answer 17

yw