Question

A dictionary has different words that only consists of letters {ACHINS}.
What will be the position of the word SACHIN in that sequence?

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{A dictionary has different words that only consists of letters {ACHINS}.}\hspace{.33em}\\~\\
& \normalsize \text{ What will be the position of the word SACHIN in that sequence?}\hspace{.33em}\\~\\

& a.)159 \hspace{.33em}\\~\\
& b.)160 \hspace{.33em}\\~\\
& c.)161 \hspace{.33em}\\~\\
& d.)162 \hspace{.33em}\\~\\

\end{align}}\)

Answer 2

do they define what a "word" is ?

Answer 3

^

Answer 4

example ACIHSN is a word

Answer 5

well the question makes sense only if we can make any random wrd

Answer 6

we can also conclude that repetition is not allowed :)

Answer 7

there are 6! of the words there as repetion is allowed

Answer 8

and S starts from 5 last 5! =120

Answer 9

yes, but we will get 601 using that.

Answer 10

but 6!-5!=600

but the answer is 601 , i m confused on that

Answer 11

1) calculate all possible combinations of words tha can be made with A fixed
2)do the same with C, H, I, N
3) now we have S and luckily the 1st wrd that can be made starting with S is SACHIN :P so can u do it now :)

Answer 12

there are 120 "words" per starting letter
the first 5 groups use up 600 slots
SACHIN will be in slot 601

Answer 13

but that is no where near your answer choices of about 160

Answer 14

yea 601 is the answer :)

Answer 15

oh lol yea

Answer 16

i wrote the choices incorrectly it was supposed to be 599,600,601,602

Answer 17

hehe e.e XD

Answer 18

playing a joke on me! how mean!

Answer 19

^

Answer 20

hallucinations happen to everyone including me

Answer 21

LAWL ( ͡° ͜ʖ ͡°)