{2} subset Power set({1, 2}) True or False I think this question is asking if the set 2 is in the power set of {1, 2}. I say True because the power set is {}, {1}, {2}, {1,2} and {2} is an element of the power set. I was just thrown off by the {2} at the start of the problem because normally id just read it asking is 2 a subset of ..... and i dont know if {2} makes a difference
So if you have a set \(\large\rm S=\{1,2\}\) Then subsets of \(\large\rm S\) are going to be: \(\large\rm \{\},~\{1\},~\{2\},~\{1,2\}\) And the power set is the set containing all of those sets, ya? So they're asking if {2} is a subset of that power set. Hmm boy I always get confused by these... I want to say that {2} is an `element of` of the power set, but not a subset of it. I might be completely wrong though :P Bah I find sets confusing... set imma go look it up lol
If the set only consists of 2 and it is an element of the power set, then isnt it technically a subset of the power set. That is what i think so i think its true but am not sure
i think you and i are thinking the same thing and also tripped up by the same confusing part
ya :) sorry i don't have a great understanding of this yet. this video is really helping me to get a grasp on it though, https://www.youtube.com/watch?v=RzMLWDiC9No if you care to check it out.
\[\large\rm \mathcal P(S)=\{\{\},~\{1\},~\{2\},~\{1,2\}\}\]So then, \(\large\rm \{\{2\}\}\subset\mathcal{P}(S)\) But I don't think {2} is a subset of P(S). Hmm. Need some expertise. @zzr0ck3r
@ganeshie8
Exactly, \(\{2\}\) is an element of powerset, not a subset. \(\{2\} \in \mathcal{P}(S)\)
100%
nice gimme medal pls
for what?
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