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Mathematics 21 Online
OpenStudy (anonymous):

FAN AND MEDAL

OpenStudy (anonymous):

A closed container has 2.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container? 0.34 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 ⋅ 10−1 0.37 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71 ⋅ 10−1 3.41 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 3.71 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71

OpenStudy (anonymous):

i think C

OpenStudy (anonymous):

@isaac4321

OpenStudy (anonymous):

Compare the decimals 56.07 and 56.7. Which comparison is correct? A. 56.07 > 56.7 B. 56.07 = 56.7 C. 56.07 < 56.7

OpenStudy (anonymous):

@iwillpraise you can not put ur question on someone else problem

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@kiamousekia 1 mole of H weights 1.008 g 1 mole = 6.02 x 10^23 particles Mass of 1 atom = 1.008 g / 6.02 x 10^23 = 1.67 x 10^-24 g

OpenStudy (anonymous):

okay....

OpenStudy (anonymous):

Lol that's real helpful

OpenStudy (anonymous):

that was helpful

OpenStudy (anonymous):

Soooooo... 2.04x10^23 atoms x 1.67x10^-24 g/atom = 3.41x10^-1 g

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

and your Right its right its C

OpenStudy (anonymous):

okay thanks so much

OpenStudy (anonymous):

Welcome :)

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