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Chemistry 22 Online
OpenStudy (anonymous):

Can you help me with 1.65?

OpenStudy (anonymous):

OpenStudy (anonymous):

@toxicsugar22 do you know?

OpenStudy (anonymous):

@aaronq can you help?

OpenStudy (aaronq):

You just have to use the formula written there at the bottom

OpenStudy (anonymous):

i understand that, but which is the T.V and the E.V??? that's what i don't understand @aaronq

OpenStudy (aaronq):

true value and experimental value. Did they not give you these?

OpenStudy (anonymous):

what's in the picture is what we got

OpenStudy (anonymous):

do you want the full question?

OpenStudy (aaronq):

really? maybe they want you to assume that the body temp is 37 Celsius

OpenStudy (aaronq):

but yeah, post the question

OpenStudy (anonymous):

it said body temp was 38.9 C

OpenStudy (aaronq):

was that supposed to be the measured temperature?

OpenStudy (anonymous):

The medicinal thermometer commonly used in the homes can be read (+or-) 0.1F, whereas those in the doctor's office may be accurate to (+or-) 0.1C, express the percent error expected from each of these thermometers in measuring a person's body temperature of 38.9C.

OpenStudy (aaronq):

ohh okay. So the true value is 38.9 C and the largest possible error is \(\pm0.1~^oC\) So \(\sf percent~error =\dfrac{|true-experimental|}{true}*100\%\) note that the absolute value bars and how it wont matter if you add or subtract 0.1 C from the value. For celsius it's: \(\sf percent~error =\dfrac{|38.9^oC-39~^oC|}{38.9^oC}*100\%\)

OpenStudy (aaronq):

Do the same for fahrenheit

OpenStudy (anonymous):

what would the exp. be for F? 102.02 is true. so would exp. be 102.01?

OpenStudy (aaronq):

102.02 F +0.1 F = 102.12 F

OpenStudy (aaronq):

or 101.92

OpenStudy (anonymous):

i'm getting .0980% (sorry it took so long, i got a phone call) @aaronq

OpenStudy (aaronq):

yep, that seems good, i would round to 0.1 % though

OpenStudy (anonymous):

Ok thank you!

OpenStudy (aaronq):

no problem!

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