Find the exact value of:
\(\Large\cos (-\frac{5\pi}{4})\)
the negative sign is throwing me off
\(\cos(-x)=\cos(x)\)
wait. so is it basically just saying \(\Large\cos (\frac{5\pi}{4})\) o-o
correct
\[-\frac{ 1 }{ \sqrt{2} }\]
@matlee we all know how to use a calculator.
your smart , i hope you do
read the rules, if you can
cos(-5pi/4) = cos(5pi/4) =cos(2pi -3pi/4) =cos(3pi/4) =cos(pi-pi/4) =-cospi/4 =-1/sqrt(2) Source: mathskey.com
@matlee and @bradely , please don't provide direct answers, I don't care what the source is. So from what i see, \(\Large\cos (-\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2}\)
So what was the purpose of putting a negative sign in there? Just to throw of poor unsuspecting students? Or is there actually something I need to do about the said negative sign?
@Nnesha @zzr0ck3r
and @satellite73 thank you for the trig cheat sheet, lot of helpful things on there
cos is even function cos(-x)= cos(x) but careful sin and tan sin(-x)=-sin(X) odd tan(-x)=-tan(x)odd
about*
so if cos (-x)= cos(x) then sec(-x)= ?
then sec(-x) would be sec(x), since sec is just the inverse function of cos
so -cos(-x)= ?
-cos(-x)= -cos(x)
yep! there is an identity to prove cos(-x)=cos(x) you'll learn n calc one i guess
funnnn
ye!
XD Thank you
np :=)
cos gives you the \(x\) value on the angle, |dw:1441072239511:dw| The bottom angle is the negative version of the top angle, but they both give the same x values.
I hope that makes sense.
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