suppose you buy a piece of office equipment for $9,000. After 6 years you sell it for a scrap value of $5000. The equipment isdeprecated linearly over 6 years. The value of the piece of equipment ater 4 years is (round to the nearest whole dollar.

Question

anonymous · Answer

line through $(0,9,000)$ and $(6,5000)$ is $$y=-\frac{2000}{3}x+9000$$

anonymous · Answer

put in $4$ for $x$

anonymous · Answer

can you please explain this to me? I got 5000 - 9000 / 6 = -4000/6  but I cant figure out my answer to that ... which is supposed to be my M because I need to use v(t)=mt+b I thought to find the value of the piece of equipment after 4 years

anonymous · Answer

$$\frac{-4000}{6}=-\frac{2000}{3}$$ same thing

anonymous · Answer

that is your $m$

anonymous · Answer

aka slope
y intercept is what you start with $9,000$ so line is 
$$y=-\frac{2000}{3}t+90000$$

anonymous · Answer

put in 4 for x

anonymous · Answer

or t

anonymous · Answer

Oh okay! How would I plug that into the TI to calculate it to find my answer?

anonymous · Answer

idk i haven't used a calculator in years http://www.wolframalpha.com/input/?i=-2000*4%2F3%2B90000

anonymous · Answer

what do you get as an answer?  87333.3333 ? what would that be to the nearest whole dollar?

anonymous · Answer

i guess $\$87333$

anonymous · Answer

seems wrong though hold on

anonymous · Answer

yeah it was wrong, i put in too many zeros

anonymous · Answer

http://www.wolframalpha.com/input/?i=-2000*4%2F3%2B9000

anonymous · Answer

$$\$6,333$$ looks a lot better

anonymous · Answer

it does. why did you type it in as -2000*4/3+9000  when the 3 should be under the -2000 and multiply that by 4?

anonymous · Answer

yes

anonymous · Answer

it doesnt make any difference $$-\frac{2000}{3}\times 4=-\frac{2000\times 4}{3}$$