Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

counting question

OpenStudy (anonymous):

If the 5 cards shown above are placed in a row so that [5] is never at either end, how many different arrangements are possible? The answer is 72...but I don't know how they got the answer...

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

[3] [2] [5] [9] [7]

ganeshie8 (ganeshie8):

forget about the given restriction how many total ways can you arrange 5 cards in a row ?

OpenStudy (anonymous):

[3] [2] [5] [9] [7] every one of this is card

OpenStudy (anonymous):

how i solve it by calc plz

ganeshie8 (ganeshie8):

|dw:1441093148752:dw|

OpenStudy (anonymous):

scientific calc

ganeshie8 (ganeshie8):

initially you have 5 cards available, so you can choose the first card in 5 ways after that, you can choose the second card in 4 ways after that, you can choose the third card in 3 ways after that, you can choose the fourth card in 2 ways after that, you can choose the fifth card in 1 ways |dw:1441093246604:dw| so total number of ways of arranging 5 cards in a row = \(5*4*3*2*1 = 120\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!