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Mathematics 14 Online
OpenStudy (anonymous):

counting question

OpenStudy (anonymous):

OpenStudy (anonymous):

hlp

OpenStudy (kropot72):

The number of arrangements with the designated card at the left end is 4! The number of arrangements with the designated card at the right end is 4! Therefore the number of arrangements that are not allowed is (4! + 4!). The total number of arrangements with no restrictions is 5!. Therefore the number of arrangements with the designated card not at either end is given by: 5! - (4! + 4!) = you can calculate.

OpenStudy (anonymous):

can u tell me how to solve by scientific calc@kropot72

OpenStudy (anonymous):

npr or ncr

OpenStudy (anonymous):

and how

OpenStudy (kropot72):

Does your calculator have a factorial function, labelled x! ?|dw:1441097323742:dw|

OpenStudy (anonymous):

then wt

OpenStudy (kropot72):

Then enter: 5 x! - (4 x! + 4 x!) =

OpenStudy (anonymous):

oh ya i understand

OpenStudy (anonymous):

but why u do only 4 +4 not 5+5

OpenStudy (anonymous):

ok i

OpenStudy (anonymous):

understand

OpenStudy (anonymous):

but can i do it by npr or ncr

OpenStudy (kropot72):

5P5 - (4P4 + 4P4) =

OpenStudy (anonymous):

ok thnks man u are the best i ll be fan of u

OpenStudy (kropot72):

You're welcome :)

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