Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
hlp
OpenStudy (kropot72):
The number of arrangements with the designated card at the left end is 4!
The number of arrangements with the designated card at the right end is 4!
Therefore the number of arrangements that are not allowed is (4! + 4!).
The total number of arrangements with no restrictions is 5!.
Therefore the number of arrangements with the designated card not at either end is given by:
5! - (4! + 4!) = you can calculate.
OpenStudy (anonymous):
can u tell me how to solve by scientific calc@kropot72
OpenStudy (anonymous):
npr or ncr
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
and how
OpenStudy (kropot72):
Does your calculator have a factorial function, labelled x! ?|dw:1441097323742:dw|
OpenStudy (anonymous):
then wt
OpenStudy (kropot72):
Then enter:
5 x! - (4 x! + 4 x!) =
OpenStudy (anonymous):
oh ya i understand
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
but why u do only 4 +4 not 5+5
OpenStudy (anonymous):
ok i
OpenStudy (anonymous):
understand
OpenStudy (anonymous):
but can i do it by npr or ncr
OpenStudy (kropot72):
5P5 - (4P4 + 4P4) =
Still Need Help?
Join the QuestionCove community and study together with friends!