How do you write a recursive and explicit formula for the sequence 15, 22, 29, 36, 43, .... ? I hope someone can explain this to me!

Question

thomas5267 · Answer

$$
A_n=A_{n-1}+7
$$
Since the last term is 7 more than then current term.

michele_laino · Answer

hint:
we can write this:
$$\Large \begin{gathered}
  {a_2} = 22 = 15 + 1 \cdot 7 = {a_1} + \left( {2 - 1} \right) \cdot 7 \hfill \
   \hfill \
  {a_3} = 29 = 22 + 7 = 15 + 2 \cdot 7 = {a_1} + \left( {3 - 1} \right) \cdot 7 \hfill \
   \hfill \
  {a_4} = 36 = 29 + 7 = 15 + 3 \cdot 7 = {a_1} + \left( {4 - 1} \right) \cdot 7 \hfill \
   \hfill \
  {a_5} = 43 = 36 + 7 = 15 + 4 \cdot 7 = {a_1} + \left( {5 - 1} \right) \cdot 7 \hfill \ 
\end{gathered} $$

anonymous · Answer

I see, then the $$a_n-1 $$ represents the preceding term.
How do you write an explicit formula for the sequence?

anonymous · Answer

Nvm, I think I'm good thank you