Need help with five Algebra 2 questions! Please help me. I'm never able to get help on this website hardly ever.
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
any particular question?
OpenStudy (misty1212):
??
OpenStudy (anonymous):
Yes! @misty1212
OpenStudy (misty1212):
best to post a specific question
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OpenStudy (anonymous):
let me pull them up!
OpenStudy (anonymous):
Okay my first question is this:
What is the graph of the absolute value equation?
y = /x/ -9
OpenStudy (misty1212):
do you know what \(y=|x|\) looks like? that is the basic starting point
OpenStudy (anonymous):
Not really. I've been having a lot of trouble with graphing :(
OpenStudy (misty1212):
it looks like a V |dw:1441118922280:dw|
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OpenStudy (misty1212):
to the right of zero it is the line \(y=x\) to the left it is \(y=-x\)
OpenStudy (anonymous):
Okay I thought so. Can the V's placement move up and down on the graph?
OpenStudy (misty1212):
when you subtract 9 outside, it moves it down 9 units
OpenStudy (anonymous):
Thats what I was about to draw.
OpenStudy (misty1212):
and output is 9 less than \(y=|x|\)
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OpenStudy (misty1212):
|dw:1441119016232:dw|
OpenStudy (anonymous):
Okay so when you have y = /x/ will it always look like a V?
OpenStudy (misty1212):
lol yeah it never changes
OpenStudy (anonymous):
And then the number at the end of the equation is where you place it.
OpenStudy (anonymous):
Sorry... Math is not my strongest subject.
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OpenStudy (misty1212):
no problem
OpenStudy (misty1212):
if it was say \(y=|x|+2\) it would be up 2 units
OpenStudy (anonymous):
Do you have time to help me with a few more?
OpenStudy (misty1212):
sure
OpenStudy (anonymous):
Thank you so much!
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OpenStudy (anonymous):
What is the graph of the absolute value equation?
y = /x+4/
OpenStudy (misty1212):
ok this one is a bit different because FIRST you add 4 THEN take the absolute value
OpenStudy (misty1212):
that shifts the V 4 units to the LEFT`
OpenStudy (misty1212):
|dw:1441119337575:dw|
OpenStudy (misty1212):
don't be confused by going to the left
think of it this way
the smallest the absolute value can be is zero, so if \(x=-4\) then \(y=|-4+4|=|0|=0\)
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OpenStudy (anonymous):
And its positive right so wouldn't it be to the right?
OpenStudy (anonymous):
Oh! Your reply came in late so I didn't see it! I got it!
OpenStudy (misty1212):
no for the reason i wrote above
don't forget the order in which you do things here
first add 4, then take the absolute value
if \(x=4\) then \(y=|4+4|=8\) not 0
OpenStudy (anonymous):
Yes, I understand. I didn't see what you said before I replied.
OpenStudy (misty1212):
it is more general than just for the absolute value
compared to \(y=f(x)\) the graph of \((y=f(x+4)\) would be shifted to the LEFT 4
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OpenStudy (anonymous):
Okay! I got it :) So the graph would have the v shifted to the left 4
OpenStudy (misty1212):
yes
OpenStudy (anonymous):
Awesome. You are so much help!
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
OpenStudy (anonymous):
:) cute!
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OpenStudy (misty1212):
quick quiz
how would \[y=|x+2|-3\] be shifted?
OpenStudy (anonymous):
okay one second
OpenStudy (anonymous):
y = /x+2/ -3 = /0/ -3
OpenStudy (misty1212):
your answer should be left or right so many units, up or down so many units
OpenStudy (anonymous):
Wait... I don't think I'm doing it right
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