What is the value of the expression 4/2^-2?
A.
½
B.
1
C.
8
D.
16
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OpenStudy (anonymous):
@Studyhelp_00002
OpenStudy (anonymous):
@GracieBugg
OpenStudy (anonymous):
@Kitten_is_back
OpenStudy (anonymous):
@amberosales
OpenStudy (anonymous):
plz help me
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OpenStudy (tkhunny):
Show your work. Stop tagging the world.
OpenStudy (anonymous):
im trying im stuck
OpenStudy (phi):
do you know how to "flip"
\[ \frac{1}{2^{-2} }\]
?
OpenStudy (anonymous):
yes
OpenStudy (tkhunny):
See, you could have shown that.
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OpenStudy (anonymous):
i did
OpenStudy (anonymous):
it is 4/2^-2
OpenStudy (phi):
what do you get when you flip
\[ \frac{1}{2^{-2}} \]?
OpenStudy (tkhunny):
No, you wrote the problem statement. You did not show that you knew how to "flip" negative exponents. You could have shown that.
OpenStudy (anonymous):
ok it is
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OpenStudy (anonymous):
i for got show me plz
OpenStudy (phi):
the "rule" is flip the fraction (bottom becomes top and vice versa)
*and*
change the exponent by multiplying the exponent by -1
OpenStudy (phi):
can you do that for
\[ \frac{1}{2^{-2}} \]
OpenStudy (phi):
here is an example
\[ \frac{1}{5^3}= \frac{5^{-3}}{1}\]
OpenStudy (anonymous):
ok
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OpenStudy (phi):
do it in two steps:
1) first, can you write the "flipped" version of 1/2^(-2) ?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
yes
OpenStudy (phi):
can you post step 1) flip 1/2^(-2)
OpenStudy (anonymous):
\[\frac{ 1 }{ 2^3 }\]
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OpenStudy (anonymous):
-3
OpenStudy (phi):
start with
\[ \frac{1}{2^{-2}} \]
now make the bottom (the \( 2^{-2}\) ) the top
and make the top (the 1) the new bottom
what do you get ?
OpenStudy (anonymous):
it is the same
OpenStudy (phi):
if you had
\[ \frac{a}{b}\]
the flipped version is
\[ \frac{b}{a} \]
OpenStudy (anonymous):
im sorry somthing so simple is hard for me
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OpenStudy (phi):
ok, practice with this
x/y
what is that flipped?
OpenStudy (anonymous):
x/y-y?
OpenStudy (phi):
x/y flipped becomes y/x
try c/d
what is that flipped?
OpenStudy (anonymous):
oooo d/c
OpenStudy (phi):
yes. now try
3/2 flipped is ?
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OpenStudy (anonymous):
2/3
OpenStudy (phi):
yes
now this one
(4*2)/(5*6)
flip that
OpenStudy (anonymous):
2*4/6*5
OpenStudy (anonymous):
1/(2-^2)
OpenStudy (phi):
try
1/(2*3)
flip that
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OpenStudy (anonymous):
humm
1/(3*2)
OpenStudy (phi):
no, (2*3)/1
just like a/b becomes b/a
c/d becomes d/c
x/y becomes y/x
(2*3)/(4*5) becomes (4*5)/(2*3)
do you see the pattern ?
OpenStudy (anonymous):
yes
OpenStudy (phi):
now try
1/(2*3)
OpenStudy (anonymous):
sorry
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OpenStudy (anonymous):
ok (2*3)/1
OpenStudy (phi):
yes.
now use that same idea on
1/(2^-2)
flip this one
OpenStudy (anonymous):
(2_^2)/1
OpenStudy (phi):
(2^-2)/1
OpenStudy (anonymous):
o woops
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OpenStudy (phi):
now when we flip things they change
1/2 is different from 2/1
but
if we have 1/(2^-2) and flip it to 2^-2/1 then *change the exponent*
so that we have 2^2/1
it turns out
that \[ \frac{1}{2^{-2}} = \frac{2^2}{1} \]
OpenStudy (phi):
so we do two things: flip and *change the exponent*
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
humm
OpenStudy (phi):
now your problem is
\[ 4 \cdot \frac{1}{2^{-2}} \]
and 1/2^-2 is 2^2, so it is now
\[ 4 \cdot 2^2 \]
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OpenStudy (phi):
2^2 means 2*2
4* 2^2 means 4*2*2
OpenStudy (anonymous):
ok nvm i got it u r just beating around the boosh sorry i figured it out thx thow