Question

Ellen wants to purchase a book that is regularly priced at $18. The book is discounted 15%. She also needs to pay a 6% sales tax on the discounted price.

What is the total amount Ellen will pay for the book?

Enter your answer in the box.

Answer 1

@Michele_Laino

Answer 2

@Loser66

Answer 3

$16.22 i believe

Answer 4

ok :)

Answer 5

after discount, the new price is:
\[\Large 18 - \left( {\frac{{15}}{{100}} \cdot 18} \right) = ...?\]

Answer 6

oops i messed up lol

Answer 7

153/10

Answer 8

@Michele_Laino

Answer 9

is it 15.3 @Michele_Laino

Answer 10

please wait, I check your result

Answer 11

ok :)

Answer 12

yes! correct!

Answer 13

ok :)

Answer 14

now, the requested price is given by the subsequent computation:
\[\Large 15.3 + \left( {\frac{6}{{100}} \cdot 15.3} \right) = ...?\]

Answer 15

15.6

Answer 16

I got a different result

Answer 17

what did you get?

Answer 18

hint:
\[\Large \frac{6}{{100}} \cdot 15.3 = ...?\]

Answer 19

0.918 @Michele_Laino

Answer 20

and
15.3+0.918=...?

Answer 21

16.128

Answer 22

i mean 16.218

Answer 23

yes! correct! That result can be rounded off to 16.22

Answer 24

so whats the final answer?

Answer 25

the final answer is 16.22

Answer 26

are you sure?

Answer 27

yes!

Answer 28

ok :)

Answer 29

here the rate of the car is:
space/time,
\[\Large \frac{{1/6}}{{3/5}} = \frac{1}{6} \cdot \frac{5}{3} = ...?\]

Answer 30

please express your result as a fraction

Answer 31

1/10

Answer 32

I'm sorry, it is wrong

Answer 33

1/10 is wrong?

Answer 34

yes!

Answer 35

5/18?

Answer 36

correct!

Answer 37

that rate is the space traveled in 1 hour

Answer 38

so the requested distance is:
distance= speed*time
\[\Large {\text{distance}} = \frac{5}{{18}} \cdot 1 = ...?\]

Answer 39

sorry i meant 5/18

Answer 40

correct!

Answer 41

is that the final answer?

Answer 42

yes!

Answer 43

okay :)

Answer 44

:)

Answer 45

@Michele_Laino

Answer 46

part A)
If I call with p the price in September, then I can write this equation:
\[\Large \begin{gathered}
p + \left( {\frac{{20}}{{100}} \cdot p} \right) = 1.5 \hfill \\
\hfill \\
or:
\\
\\
1.2p = 1.5 \hfill \\
\end{gathered} \]
please solve for p

Answer 47

p=1.25

Answer 48

correct!

Answer 49

is that the final answer for part A?

Answer 50

yes!

Answer 51

ok now part b?

Answer 52

here, we note that:
in september the earned money is:
\[\Large 900 \cdot \left( {1.25 \cdot \frac{{40}}{{100}}} \right) = ...?\]
whereas in october, the earned money is:
\[\Large 700 \cdot \left( {1.5 \cdot \frac{{40}}{{100}}} \right) = ...?\]
please compute both amounts of money

Answer 53

i got 450 for september and 420 for october

Answer 54

correct!
So, what is your answer?

Answer 55

um its says choose one... for the first one these are the multiple choices.. september or october and the other choose one are... $30, $75, or $190

Answer 56

yes!
450-420=...?

Answer 57

30

Answer 58

so what are your options?

Answer 59

for which one... there are two answers for part b

Answer 60

yes! for part B) there are 2 options

Answer 61

right

Answer 62

first option: is september or october?

Answer 63

yes

Answer 64

please choose

Answer 65

september

Answer 66

correct!
second option: is 30, 75 or 190?

Answer 67

yea

Answer 68

$30?

Answer 69

correct!

Answer 70

yay! so september and 30

Answer 71

yes!

Answer 72

@Michele_Laino

Answer 73

part A)
hint:
your line passes at point (0,0), namely the origin

Answer 74

i got... a,c and e

Answer 75

correct!

Answer 76

yay! thanks so much! :)

Answer 77

:)