The midpoint of UV is (5,-11). One of the coordinates are U(3,5). Find V
\[\text{ the midpoint of the line segment from point } (a,b) \text{ \to } (c,d) \text{ is } \\ (\frac{a+c}{2},\frac{b+d}{2})\]
you are given: \[\frac{3+c}{2} =5 \text{ and } \frac{5+d}{2}=-11\]
where (c,d) is point V
Would I have to plug something into the formula? How would the end result look
do you know how to solve equations yet?
maybe not... I guess since you are asking how to solve (3+c)/2=5 and also solve (5+d)/2=-11
the first I would do would be to multiply both sides by 2
for both equations
Ok so that would give 5+d=-22?
yes for the second equation you have d+5=-22
and then 3+c=10
do you the +5 on the side with d on it you are going to minus 5 on both sides because you know 5-5=0 so you will have d by itself
and that is right for the first equation so far
And then you do the same to the other one too?
well not subtract 5 on both sides but subtract 3 on both sides yes
So d=-27 and c=7?
ok great now remember (c,d) is the point V so your answer would be (7,-27) is the other endpoint V
so the midpoint of (7,-27) and (3,5) is \[(\frac{3+7}{2},\frac{-27+5}{2})=(\frac{10}{2},\frac{-22}{2})=(5,-11)\]
Ok great I get it now
cool stuff have a good day :)
Thank you very much for your help! My sister doesn't know how to do this, thank you
well go teach her then
Ok i will now
Join our real-time social learning platform and learn together with your friends!