In 2010 a company installed a new machine in one of its factories at a cost of $680,000. The
machine is linearly depreciated over 30 years with a scrap value of $80,000.
4. Find an expression for the machine value in the t th year of use (0

Question

In 2010 a company installed a new machine in one of its factories at a cost of $680,000. The
machine is linearly depreciated over 30 years with a scrap value of $80,000.
4. Find an expression for the machine value in the t th year of use (0 < t < 30).

danjs · Answer

sorry, it is scrap value...

danjs · Answer

linearly depreciated means it is a line with constant slope,   y = m*x+b

anonymous · Answer

I got -20000
so m ans is v(t) = -20,000t + 680000?

danjs · Answer

the slope will be how much it has gone down in over that 30 years time...

m = (680,000 - 80,000) / 30

danjs · Answer

looks good, the y intercept is the starting value when time t=0

anonymous · Answer

my answer is right?  
the second part is:   Find the machine’s value in the year 2024.
how do I calculate that?

danjs · Answer

yes correct,  they installed the achine in 2010, so 2024-2010 = 14 years of depreciation, let t=14 years