Question

What did I do wrong in this problem!? Help! ill give medals

Answer 1

drummer chicks unite!!! :D

Answer 2

sorry, that was random

Answer 3

woah!

Answer 4

well what's the problem list the equation so we can help you

Answer 5

i took a picture of all my work- its i the attachment above ^

Answer 6

i know u guys are here do something already

Answer 7

looking backwards it seems like you have in that thinking that -4(2) = -24

Answer 8

The quadradic formula?
is that what your doing

Answer 9

this is the problem: \[\frac{ x + \frac{ 5 }{ x } }{ 1+\frac{ 6 }{ x } }=4x\]

Answer 10

\[\frac{-24 \pm 2 \sqrt{159}}{6}= \frac{\frac{-24}{2} \pm \frac{2 \sqrt{159}}{2}}{\frac{6}{2}} \\ \\ =\frac{-12 \pm \sqrt{159}}{3}\]

Answer 11

Try mathway

Answer 12

other than that your work looks great
just end part needs fixing

Answer 13

im confused :(

Answer 14

in the end when you divided -24 by 2 you wrote -4
this is not true

Answer 15

why cant i simplify the numerator and denominator like afraction?

Answer 16

\[\frac{-24 \pm 2 \sqrt{159}}{6} \\ \text{ you can separate the fraction } \\ \\ \frac{-24}{6} \pm \frac{2 \sqrt{159}}{6} \\ -4 \pm \frac{\sqrt{159}}{3}\]

Answer 17

maybe that is what you meant to do

Answer 18

Look at your last step, the solution.
Now look one step up.

Answer 19

-24 and 6 simplify to -12 and 3, not -4 and 3

Answer 20

ahhh there we go, that makes more sense to me

Answer 21

You made a small mistake in the very last step.

Answer 22

i did this same thing last time lol thanks!!

Answer 23

\(\dfrac{-24 \pm 2\sqrt{159} }{6} = \dfrac{\cancel 2 (-12 \pm \sqrt{159})}{\cancel 2(3)}\)

Answer 24

just curious
so this didn't make any sense:
\[\frac{-24 \pm 2 \sqrt{159}}{6}= \frac{\frac{-24}{2} \pm \frac{2 \sqrt{159}}{2}}{\frac{6}{2}} \\ \\ =\frac{-12 \pm \sqrt{159}}{3}\]
?

Answer 25

@freckles You figured it out way back.

Answer 26

i kinda understand that way that you wrote, the other way was easier lol

Answer 27

ok well as long as you get it