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Mathematics 16 Online
OpenStudy (anonymous):

https://static.k12.com/bank_packages/files/media/mathml_b16a76b592b37eac706ce3f3dad8e5cd8f71bfb4_1.gif

OpenStudy (anonymous):

What value of p solves the equation?

OpenStudy (anonymous):

i'd say drop the p^-5

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

\[-\frac{ 1 }{ 243 }=\frac{ 1 }{ p^5 }\]

OpenStudy (anonymous):

p=?

OpenStudy (anonymous):

wait u have to find out p?

OpenStudy (anonymous):

yes p=?

OpenStudy (anonymous):

@Nnesha can u help him i have no clue

OpenStudy (anonymous):

@Nnesha got any thing?

OpenStudy (anonymous):

well you can't keep the exponent negative

Nnesha (nnesha):

\[\huge\rm p^{-5}=\frac{ 1 }{ 243 }\] 2 ways to find value of p first one is change negative to positive exponent and then cross multiply 2nd one ) what number to the 5th power equal to 243 ?

OpenStudy (anonymous):

3^5

Nnesha (nnesha):

uh-oh not u

OpenStudy (anonymous):

yea

Nnesha (nnesha):

yea what ?

OpenStudy (anonymous):

hey at least im learning

OpenStudy (anonymous):

hurry mt time is allmost out

OpenStudy (anonymous):

my

Nnesha (nnesha):

good.

Nnesha (nnesha):

you didn't answer my question shady

OpenStudy (anonymous):

ok what how do i find that out?

OpenStudy (anonymous):

how much time u have left?

OpenStudy (anonymous):

3min

OpenStudy (anonymous):

omg

Nnesha (nnesha):

\[\huge\rm p^{-5}= \frac{1}{p^5}\]right \[\huge\rm \frac{ 1 }{ p^5 } =\frac{ 1 }{ 243 }\] now cross multiply then take 5th root both sides

OpenStudy (anonymous):

ok how dop i cross multiplyy

OpenStudy (anonymous):

1min

Nnesha (nnesha):

|dw:1441144019060:dw| like this

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