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Mathematics 20 Online
OpenStudy (tmagloire1):

Ap calc ab please help! thanks in advance Which one of the following statements is true? If f ′′(x) > 0 on the interval (a, b) then f(x) is concave down on the interval (a, b). If f ′(x) > 0 on the interval (a, b) then f(x) is increasing on the interval (a, b). If f ′(c) = 0, then x = c is a relative maximum on the graph of f(x). None of these are true.

OpenStudy (phi):

concave down is \( \cap\) shaped say f(x)= x^2 (which we know is a parabola with \( \cup \) shape f'(x)= 2x and f''(x)= 2. f'(x) > 0 means the slope of the tangent line is rising. i.e. the function is rising f'(c) =0 means c could be a max, min or inflection.

OpenStudy (tmagloire1):

so in this case the answer is C since f'(c) =0 is the rel. max min inflect?

OpenStudy (tmagloire1):

@phi

OpenStudy (anonymous):

The second statement is correct also

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