Question

Fan and medal , HELP PLEASEEE

A satellite is in circular orbit 25,000 miles above Earth.
Write an equation for the orbit of this satellite if the origin is at the center of the Earth.
Use 8,000 as the diameter of the Earth. ??

Answer 1

Ok so this is the equ of a circle which is :
(x-a)^2+(y-b)^2=R^2 right?

Answer 2

yeees

Answer 3

Leyla ente 3arabiye? :p

Answer 4

Ok so let us get the coordinate of the center and as it says that the center of the satellite is of the earth soo...

Answer 5

??

Answer 6

Then the center which is taken as origin has coordinates O(0,0) so now we can write the equ. As x^2-y^2=R^2

Answer 7

Sorry x^2+y^2=R^2

Answer 8

Understood till now??

Answer 9

yes

Answer 10

but im still confused

Answer 11

Ok and the satellite is 25000 miles over the earth and the earth has a diameter of 8000 miles thus a radius of 4000miles therefore from the center pf the earth to the satellite which is the radius of the equation is 25000+4000=29000 therefore the equ. Gives us x^2+y^2=25000^2

Answer 12

Sorry 29000^2*

Answer 13

Whats confusing you?

Answer 14

I understand now , I thought that , I need more process than that

Answer 15

you know more formulas etc , but thank you so much !

Answer 16

Your welcome :) btw are you arab?

Answer 17

not I'm not lol, why ?

Answer 18

If you need to find the amount of time the satellite takes to complete one orbit, this page should help you.
http://www.1728.org/kepler3a.htm
1.1613 days by the way

Answer 19

thank you @wolf1728

Answer 20

thanks Leyla :-)

Answer 21

Hehe nothing forget it :p

Answer 22

That page has the formula you will need

time = sq root[(4*PI^2 * radius^3) / (G*m)]
If you need some help with that, I'll help you

Answer 23

well I dont need the time, but thank you anyway, BUT i need help with a different question you think that you can help? @wolf1728

Answer 24

Well, ask the question and let's see.

Answer 25

Center at (2, 4), tangent to x-axis

Answer 26

Is that for a circle?

Answer 27

yes

Answer 28

Okay, if the circle is tangent to the x-axis and center is at x=2 y =4 then it would need a radius of 4.

Answer 29

Circle's equation formula is:
(x -a)² + (y -b)² = r²
where center = (a, b)

Answer 30

so 2 is a, and 4 is b ?

Answer 31

yes and r^2 would be 16

Answer 32

thank youuuuuuuuu so much , I feel like i love u right now lol jk , but thank seriusly :)

Answer 33

ok you are welcome :-)

Answer 34

heeyy hold on! , i dont want to bother you but i have a question,
Center in the first quadrant: tangent to x=5 the x-axis and the y-axis.
So this question is kinda the same like the previus ?

Answer 35

@wolf1728