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Estimate the area under the curve f(x) = 16 – x^2 from x = 0 to x = 3 by using three inscribed (under the curve) rectangles. Answer to the nearest integer.
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Would I take the integral of the function from 0 to 3?
yup this it @Ephemera use integral u know how use it right ?
\[\int\limits_{0}^{3}16-x ^{2} \] That would be it correct?
yup
\[\left[ 16x-\frac{ x^3 }{ 3 } \right]\]
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(16(3)- 3^3/3) - 0 = 48-9 = 39 this the area @Ephemera
@dinamix just solved it myself and got 39 as well. Appreciated.
@dinamix I got this one wrong too....could it be a faulty system?
so what fault u sopke @Ephemera
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