Question

decide whether the equation is a trigonometric identity.
cos^2 (x)(1+tan^2 (x))=1
sec(x)tan(x)(1-sin^2(x)=sin(x)

Answer 1

I will fan and medal

Answer 2

\(\cos^2(x)(1+\tan^2(x))=\cos^2(x)+\cos^2(x)\dfrac{\sin^2(x)}{\cos^2(x)}=\cos^2(x)+\sin^2(x)=?\)

Answer 3

=1

Answer 4

For the second one, \[\cos^2(x)=1-\sin^2(x)\]

So you have

\[\sec(x)\tan(x)\cos^2(x)=\frac{1}{\cos(x)}\frac{\sin(x)}{\cos(x)}\cos^2(x)=?\]

Answer 5

\[\sec(x) = \frac{ 1 }{ \cos(x)}\] i help u litttle mate

Answer 6

@zzr0ck3r why give him answer directly ?

Answer 7

thats not good for him

Answer 8

right ?

Answer 9

thanks both of you for the help