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Chemistry 7 Online
OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

A) 10.5g= kg B) 1.57km= m C)3.54ug= g D) 3.5mol= umol E) 1.2L= ml F)358cm^3 = M^3 G)548.6ml= cm^3

OpenStudy (anonymous):

complete the following conversions

OpenStudy (anonymous):

@aaronq

OpenStudy (anonymous):

@MikeyMaximum

OpenStudy (aaronq):

http://www.pasadena.edu/files/syllabi/cvbilicki_1869.PDF This should be able to help you

OpenStudy (anonymous):

@aaronq i used that but i still need help

OpenStudy (aaronq):

What do you need help with?

OpenStudy (anonymous):

like i dont understand how you find like hoe many g equal kg

OpenStudy (anonymous):

how**

OpenStudy (aaronq):

I'll show you with an example. A) 10.5g to kg from that table in the link \(\sf 1 kg = 1000 g\) Now we need to use dimensional analysis - that just means we need to use the value they gave us and rearrange it to cancel out the "g" units and leave the "kg" units. to do so we need the "g" at the bottom and the "kg" at the top: \(\sf \dfrac{1kg}{1000g}\) Now we just multiply by our value 10.5 g, the "g" units cancel out \(\sf \dfrac{10.5g}{1}*\dfrac{1kg}{1000g}=\dfrac{10.5\cancel g}{1}*\dfrac{1kg}{1000\cancel g}\) Using a calc, were left with: \(\sf \dfrac{10.5kg}{1000}=0.0105~kg\)

OpenStudy (aaronq):

Just look at the units

OpenStudy (anonymous):

okay i got it know thanks

OpenStudy (aaronq):

awesome, no problem

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