Question

Algebra 2

Find the quotient.

2x-3/x/7/x^2

A. 7/x(2x-3)
B. 7x/2x-3
C. 2x-3/7x
D. x(2x-3)/7

Answer 1

\[\huge\rm \frac{ \frac{ 2x-3 }{ x } }{ \frac{ 7 }{ x^2 } }\] like this ?

Answer 2

so the answers is C @Nnesha

Answer 3

how did you get it ?

Answer 4

I just saw what u typed me and i figure out that is was exacly urs :) @Nnesha so I'm right?

Answer 5

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge\rm \frac{ \frac{ 2x-3 }{ x } }{ \frac{ 7 }{ x^2 } }\] like this ?
\(\color{blue}{\text{End of Quote}}\)
i just asked a question
is this ur question ?

Answer 6

yes is like that the question I'm asking @Nnesha

Answer 7

okay change division to multiplication
multiply the top with the `reciprocal` of the bottom fraction

Answer 8

so i see that the answer is C @Nnesha right?

Answer 9

please show ur work so i can check !

Answer 10

I did this 2x-3/7x cuz I cancel out the x^2

Answer 11

I really dont know how to slove it :( @Nnesha

Answer 12

here is an example \[\huge\rm \frac{ \color{Red}{\frac{ a }{ b }}}{ \frac{ c }{ d} }= \color{ReD}{\frac{a}{b}} \times \frac{d}{c}\]

Answer 13

what is the reciprocal of the bottom fraction ??

Answer 14

x and 7

Answer 15

what's reciprocal of 7/x^2 ??

Answer 16

reciprocal of 3/2 is 2/3

Answer 17

7/x^2

Answer 18

that's the original fraction what's reciprocal of that ?

Answer 19

i mean x^2/7 @Nnesha

Answer 20

yes right!

Answer 21

so multiply \[\huge\rm \frac{ 2x-3 }{ x } \times \frac{ x^2 }{ 7}\] now multiply the numerator by numerator and denominator by denominator

Answer 22

I got C

Answer 23

gtg sorry no it's not c

Answer 24

So D?