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Mathematics 18 Online
OpenStudy (dumbsearch2):

Write z = -5 + 5i in trigonometric form.

OpenStudy (dumbsearch2):

OpenStudy (dumbsearch2):

D?

OpenStudy (anonymous):

|dw:1441163170659:dw|

OpenStudy (surry99):

Hint:Sketch the point it on the complex plane

OpenStudy (dumbsearch2):

I found -(pi)/(4)

OpenStudy (dumbsearch2):

before

OpenStudy (anonymous):

??

OpenStudy (anonymous):

|dw:1441163275849:dw|

OpenStudy (dumbsearch2):

What does that graph mean?

jimthompson5910 (jim_thompson5910):

-5 + 5i is in the form a+bi a = -5 b = 5 you can plot a+bi on the complex number plane as the ordered pair (a,b) which is why satellite73 plotted the point (-5,5)

OpenStudy (anonymous):

it means the angle is easy to find if you use arctangent here it will not work because you are in the wrong quadrant

OpenStudy (anonymous):

if you took \(\tan^{-1}(-1)\) you get \(-\frac{\pi}{4}\) but you are not in quadrant 4, you are in quadrant 2

OpenStudy (dumbsearch2):

So it's 3pi/4 instead, right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you cannot use arctan unless you are in quadrant 1 or 4

jimthompson5910 (jim_thompson5910):

well you can use arctan, just add on pi to get to the right quadrant

OpenStudy (dumbsearch2):

?

OpenStudy (anonymous):

you have to either know it, or use \[\cos(\theta)=\frac{a}{r}\] and \[\sin(\theta)=\frac{b}{r}\]

jimthompson5910 (jim_thompson5910):

as satellite73 said, arctan(-1) = -pi/4 add on pi to get to 3pi/4 (-pi/4) + (pi) = (-pi/4) + (4pi/4) = (-pi+4pi)/4 = 3pi/4

OpenStudy (anonymous):

or what @jim_thompson5910 said, but in any case you have to know what quadrant you are in before you start

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