Question

3-2{7x-[-2(3x-1)+3(5x-3^2)]}
I feel like i got it buttttt get confused plzz hpl

Answer 1

start from the innermost parentheses/brackets and work your way outside

let's start with -2(3x-1) = ?

Answer 2

+6x + 2?

Answer 3

almost, check the sign on 6x

Answer 4

i get confused with the negatives and positives..

Answer 5

oh -6x

Answer 6

right

Answer 7

Can i show you how i wrote it?

Answer 8

negative*positive = negative

Answer 9

sure

Answer 10

3-2 {7x-[-6x+2) + (15x-27)]
3+ - 14x + 12x -4 + -30x +54
i think im doing something wrong.. i dont know

Answer 11

you did all of that in one step?
if so I think you are doing too many steps in one step

Answer 12

what ?

Answer 13

I'm just saying because you did so many steps in one step you have made a couple of mistakes

Answer 14

maybe..

Answer 15

no i'm sure

Answer 16

I think @Vocaloid was going to take you through the process

Answer 17

Yeah idk

Answer 18

if i were you I would use the distributive property for the inner parts then move on to the outer parts

Answer 19

@glitterythings [-2(3x-1)+3(5x-3^2)] find this first and after {7x-[-2(3x-1)+3(5x-3^2)]}

Answer 20

I did that i thought , i might of skipped a step hold on

Answer 21

Ill just figure it out myself thank you guys!

Answer 22

\[3-2{7x-[-2(3x-1)+3(5x-3^2)]} \\ \text{ like first things I would do } \\ -2(3x-1) \text{ and } 3(5x-3^2)\]

Answer 23

I did that.. but i didnt put it in

Answer 24

that problem did not copy over to latex well

Answer 25

[-2(3x-1)+3(5x-3^2)] = 9x-26

Answer 26

oh i get what you guys are trying to tell me

Answer 27

\[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\}\]
there we go

Answer 28

then it would be
3- 2{7x - [-2(3x-1) + 3(5x - 9)] right?

Answer 29

isn't that thing in the [ ] 9x-25?

Answer 30

@dinamix

Answer 31

yup it is

Answer 32

i make mistake

Answer 33

{7x-[-2(3x-1)+3(5x-3^2)]} =7x-9x+25 =-2x+25

Answer 34

\[3-2\{7x-[-2(3x-1)+3(5x-3^2)]\} \\ 3-2\{7x-[-6x+2+15x-27]\} \\ 3-2\{7x-[9x-25]\} \\ \]

Answer 35

anyways @glitterythings maybe you can try from here?

Answer 36

yeah i can !

Answer 37

@freckles u find it 4x-(4!+4!-1)

Answer 38

@dinamix im working on it rn :)

Answer 39

i got 4x - 47

Answer 40

yup @glitterythings this the answer ;D

Answer 41

Ty :D

Answer 42

i have another question it has to do the same thing , and i think i did it wrong lol.

Answer 43

ok ask @glitterythings

Answer 44

4y^2 - 3 {2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]}

Answer 45

Start with this [(4y^2-y+2) - (3y^2 +2y-5)] u should try with me okey @glitterythings

Answer 46

i am i solved, but answer is wrong.
The answer is supposed to be y^2 - 9y +21

Answer 47

ill re write again :)

Answer 48

does everything become negative except for 5?

Answer 49

u find it y^2-9y+21 ?

Answer 50

not yet

Answer 51

cuz i find like that

Answer 52

you did? ugh idk what im doing wrong

Answer 53

yup ,ok first i show my method start [(4y^2-y+2) - (3y^2 +2y-5)] this and tell me what u find okey

Answer 54

i want see where is your mistake

Answer 55

4y2 - 3y2 = 1
-y+2y = 1
2 + -5 = -3?

Answer 56

i might be doing my math wrong

Answer 57

yup i find your mistake u forget Distribution - on this equeation - (3y^2 +2y-5)

Answer 58

oh lol

Answer 59

it would be -3y2 -2y +5?

Answer 60

yup

Answer 61

u have to focus @glitterythings (sorry if i was rude)

Answer 62

so then [ y2 -3y + 7?]

Answer 63

you arent.

Answer 64

yup this

Answer 65

{2y^2 -[(4y^2-y+2) - (3y^2 +2y-5)]} now second try for this

Answer 66

@glitterythings

Answer 67

oh i thought i did lol

Answer 68

so u find it @glitterythings

Answer 69

i think so.

Answer 70

y2 + 3y -7?

Answer 71

yup

Answer 72

OMG I FOUND ITT!

Answer 73

YAY THANKS SO MUCH!

Answer 74

we didnt do it really u have to complete it -_-

Answer 75

oh well i figured it out lol but okay lets complete it

Answer 76

give me your steps okey

Answer 77

so then you multiply by -3
4y2 -3 (y2+3y - 7)
4y2-3y2 - 9y +21
= y2 -9y+21

Answer 78

thank you for being patient w me.

Answer 79

yup this @glitterythings no problem u are welcome but i hope u understand the steps

Answer 80

yeah i do, its like PEMDAS
and you have to solve everything in brackets,

Answer 81

ok that s make feel happy to help u ^^

Answer 82

:)

Answer 83

@glitterythings any other question ?