Question

Can Someone Explain This To Me Please??

Answer 1

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Answer 2

parallel lines will have the same slope...so we need to find the slope of 2x - 3y = -12. Now in y = mx + b form, the slope is in the m position....so we need to turn 2x - 3y = -12 into y = mx + b form. Do you know how to do that ?

Answer 3

Divide -12 by 2x, right?

Answer 4

2x - 3y = -12 --- subtract 2x from both sides
-3y = -2x - 12 -- now we need to divide both sides by -3
y = 2/3x + 4

so the number in the m position, the slope, is 2/3

are you following me ?

Answer 5

mhm

Answer 6

Wait, I'm not sure I understand completely.
So the first step would be
3y = -14x?

Answer 7

so we have to have a slope(m) of 2/3
Now we use y = mx + b
slope (m) = 2/3
(-3,4)...x = -3 and y = 4
now since we have our slope and our x and y points, we need to find b, the y intercept
4 = 2/3(-3) + b
4 = -6/3 + b
4 = -2 + b
4 + 2 = b
6 = b

so our parallel line is : y = 2/3x + 6
questions ?

Answer 8

you are making a mistake by adding unlike terms.
you cannot add -2x to and -12..they are unlike terms.

2x - 3y = -12 --- subtract 2x from both sides
-3y = -2x - 12
see how I did that....

Answer 9

oops...you cannot add -2x to -12

Answer 10

-3y = -2x - 12 --- now we divide both sides by -3 to get y by itself
(-3/-3)y = (-2/-3)x -12/-3
y = 2/3x + 4
get it ??

Answer 11

ooh ok. I understand it now. Thanks!!

Answer 12

then you just use y = mx + b and sub in your slope and your points and solve for b, the y intercept.....just like I did above.