Question

Imaginary complex numbers

Answer 1

THEY ARE EVERYWHERE!!!!!

Answer 2

I've been asked to solve this equation, however when I get to certain step I get stuck and don't know what to do \[x^2+2x+3=0\]

Answer 3

What step?

Answer 4

\[(-2\pm \sqrt{4-12})/2\]

Answer 5

my bad I meant \[-2\pm \sqrt{-8}/2\]

Answer 6

\[\sqrt{4-12}=\sqrt{-8}=\sqrt{-1*8}=\sqrt{-1}\sqrt{8}=i\sqrt{8}=i\sqrt{4*2}=i\sqrt{4}\sqrt{2}=2i\sqrt{2}\]

Answer 7

ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooohohohhohhohoohohohohohohohoohohohohohhhhhhhhhhhhhhhh

Answer 8

Yoou should end up with \(-1\pm i\sqrt{2}\)

Answer 9

I get it.

Answer 10

word

Answer 11

Thank you

Answer 12

np

Answer 13

How did you get the -1 tho

Answer 14

\(-8=-1*8\)

Answer 15

no, I'm talking about the one in -1pmisqrt(2)

Answer 16

\(\dfrac{-2\pm2i\sqrt{2}}{2}=\dfrac{-2}{2}\pm \dfrac{2i\sqrt{2}}{2}=-1\pm i\sqrt{2}\)

Answer 17

what about the 2i, what happened to the 2?

Answer 18

\[\dfrac{-2}{2}\pm\dfrac{2i\sqrt{2}}{2}=\dfrac{\cancel{-2}}{\cancel{2}}\pm\dfrac{\cancel{2}i\sqrt{2}}{\cancel{2}}=-1\pm i\sqrt{2}\]

Answer 19

\[\dfrac{ab+cb}{b}=a+c\]

Answer 20

alright I get it now thank you

Answer 21

np