Question

Help with this parabola, 3x^2 +4x+12

Answer 1

@Nnesha

Answer 2

well I can tell you its positive definite

Answer 3

statement ?
factor ?
solve for x ?
graph ?
write in vertex form?
find vertex point ?
what is axis sym ?

Answer 4

I dont know how to find the zeros

Answer 5

alright zeros(solutions , x-intercept)
you can use quadratic formula
`OR` you can factor it

Answer 6

which one is easy for you ? factors or quadratic formula ?

Answer 7

Factors

Answer 8

ohh well nvm
you have to apply the quadratic formula \[\huge\rm x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 9

ax^2+bx+c quadratic equation
where a=leading coefficient
b=middle term
c-constant term
so what is a
b and c in that equation ?

Answer 10

\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant`
you can use this to find if the equation is factorable or not
if ` b^2-4ac > 0` then there are 2 real zeros

if ` b^2-4ac = 0` then there is one real root
if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)

Answer 11

zeros is another word they use for solutions and x-intercept

Answer 12

can u show me how to write it in vertex form .. @Nnesha

Answer 13

complete the square
y=a(x-h)^2+k ?

Answer 14

o thats all lol... im now doing this ..thanks

Answer 15

i mean convert 3x^2 +4x+12 into y=a(x-h)^2+k <---(vertex form) b using completing the square method :=)

Answer 16

i know what u meant thanks

Answer 17

np :)

Answer 18

so it would be 3x^2+(4x/2)^2+......+12-.....
(3x^2+4x+4)+12-4
(3x+2)^2+8
is this correct

Answer 19

i think i did something wrong

Answer 20

okay you need to complete the square of (3x^2+4x)
it would be great if you take out the 3

Answer 21

i've to go rn cya later

Answer 22

ok