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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910, @dan815
OpenStudy (anonymous):
@jdoe0001 ,@emily_wilson
OpenStudy (anonymous):
@emily_wilson
OpenStudy (anonymous):
r u there
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
can u help me with my homework its algebra 1
OpenStudy (anonymous):
Okay I can try, am I supposed to do all of that?
OpenStudy (anonymous):
ill do it with u though
OpenStudy (anonymous):
@beckyg111
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OpenStudy (anonymous):
what is the paper/book called?
OpenStudy (anonymous):
springboard
OpenStudy (anonymous):
the green/rainbow one?
OpenStudy (anonymous):
ya why
OpenStudy (anonymous):
I cant read all of the picture
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OpenStudy (anonymous):
which one
OpenStudy (anonymous):
13
OpenStudy (anonymous):
@haleyright
OpenStudy (anonymous):
13 right?
OpenStudy (anonymous):
yeah mostly just the word problems
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OpenStudy (anonymous):
the 2 cutoff words are equation and equal
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (haleyright):
this is hard
OpenStudy (anonymous):
i know
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OpenStudy (haleyright):
srry
OpenStudy (anonymous):
@_alex_urena_
OpenStudy (haleyright):
i tried to understand but its complicated
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
anybody there who can help me
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OpenStudy (anonymous):
pls @dan815
OpenStudy (anonymous):
@kiamousekia
OpenStudy (anonymous):
yay @jim_thompson5910 ur here
OpenStudy (anonymous):
and @dan815
jimthompson5910 (jim_thompson5910):
which one are you stuck on?
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OpenStudy (anonymous):
i need help on 13-15, 17, 21, 25, 26, 27:b, 28, 34, 35, 36, 37, 38, 39:a,b, 40.
i know its a lot pls forgive me
OpenStudy (anonymous):
nvr mind i dont need help on 28
OpenStudy (anonymous):
@jim_thompson5910 , @dan815 r u there
jimthompson5910 (jim_thompson5910):
well there are a lot of similar problems, so why not do it where we help with a few and you practice on the rest?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
lets start with 13-15
OpenStudy (dan815):
okay so lets saw for a member
for 1 year he just pays 35
a NON-member will pay lets say 5 dollars every time he uses the gym
let n the number of uses
lets see at what number of uses the
member = non member
35=5*n
when n=7, 5*7=35
so a non member if he uses the gym 7 times he will pay the same as a guy who payed for a whole year, if he uses the gym more than 7 times he will have to pay more than the guy with a membership, if he uses the gym less than 7 times he will have to pay less
Now for your question instead of 5 dollars every time he uses, they have a different number or some random number k
jimthompson5910 (jim_thompson5910):
I'm stumped. It seems like there's information missing in #13. How much does it cost per visit? It doesn't say.
jimthompson5910 (jim_thompson5910):
is the problem cut off or something?
OpenStudy (anonymous):
no
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jimthompson5910 (jim_thompson5910):
@dan815 where did you get those values from?
OpenStudy (anonymous):
it says that the cost of being a member of the frequent visitor program = the cost of not being a member
OpenStudy (dan815):
just made it up for an example, instead of 5 i think ninja has to use a variable there
OpenStudy (anonymous):
the variable is n
OpenStudy (anonymous):
which is the number of visits per year
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OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
he left
jimthompson5910 (jim_thompson5910):
well I still think there's missing info, but anyway, let's say the cost per day is k dollars. The k is some unknown number
if you visit n times for that year, then it costs k*n dollars
OpenStudy (anonymous):
@_
jimthompson5910 (jim_thompson5910):
set that equal to the 5 dollar yearly fee to get
k*n = 5
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jimthompson5910 (jim_thompson5910):
make sense?
OpenStudy (anonymous):
so thats the equation for 13, right?
jimthompson5910 (jim_thompson5910):
do you see how I formed it?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
what about 14 and 15
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jimthompson5910 (jim_thompson5910):
I think they want you to solve for n
jimthompson5910 (jim_thompson5910):
in #14
OpenStudy (anonymous):
oh let me try
OpenStudy (anonymous):
is it 5?
jimthompson5910 (jim_thompson5910):
get n all by itself in the equation `k*n = 5`
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OpenStudy (anonymous):
oh let me try it that way
OpenStudy (anonymous):
how do u divide 5 by k
OpenStudy (anonymous):
nvr mind how do u get n by itself
jimthompson5910 (jim_thompson5910):
you just leave it like that, so you'd have
\[\Large n = \frac{5}{k}\]
jimthompson5910 (jim_thompson5910):
that's what you'd have after dividing both sides by k
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OpenStudy (anonymous):
and then
jimthompson5910 (jim_thompson5910):
if you knew the value of k (the number it represents), then you could replace k with that number and divide
jimthompson5910 (jim_thompson5910):
but we don't know what k is so we leave it like 5/k
OpenStudy (anonymous):
ok so thats #14
OpenStudy (anonymous):
is it?
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jimthompson5910 (jim_thompson5910):
yeah
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
#15
OpenStudy (anonymous):
how do u do number 15
OpenStudy (anonymous):
nvrmind i know that
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OpenStudy (anonymous):
#17??
jimthompson5910 (jim_thompson5910):
what would be the answer to #15
OpenStudy (anonymous):
actually i dunno could u help me
OpenStudy (anonymous):
u there
jimthompson5910 (jim_thompson5910):
give it a try and tell me what you think
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OpenStudy (anonymous):
is it 5 divided by the money.......i dunno!
jimthompson5910 (jim_thompson5910):
what does n represent
OpenStudy (anonymous):
the # of visits??
jimthompson5910 (jim_thompson5910):
yes, so 5/k represents the number of visits (because it's equal to n)
jimthompson5910 (jim_thompson5910):
if k = 1, then 5/k = 5/1 = 5
basically saying if the price per visit is $1, then you'd have to make 5 visits for the two costs to be equal
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