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Mathematics 7 Online
OpenStudy (anonymous):

Fan and Medal

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910, @dan815

OpenStudy (anonymous):

@jdoe0001 ,@emily_wilson

OpenStudy (anonymous):

@emily_wilson

OpenStudy (anonymous):

r u there

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

can u help me with my homework its algebra 1

OpenStudy (anonymous):

Okay I can try, am I supposed to do all of that?

OpenStudy (anonymous):

ill do it with u though

OpenStudy (anonymous):

@beckyg111

OpenStudy (anonymous):

what is the paper/book called?

OpenStudy (anonymous):

springboard

OpenStudy (anonymous):

the green/rainbow one?

OpenStudy (anonymous):

ya why

OpenStudy (anonymous):

I cant read all of the picture

OpenStudy (anonymous):

which one

OpenStudy (anonymous):

13

OpenStudy (anonymous):

@haleyright

OpenStudy (anonymous):

13 right?

OpenStudy (anonymous):

yeah mostly just the word problems

OpenStudy (anonymous):

the 2 cutoff words are equation and equal

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (haleyright):

this is hard

OpenStudy (anonymous):

i know

OpenStudy (haleyright):

srry

OpenStudy (anonymous):

@_alex_urena_

OpenStudy (haleyright):

i tried to understand but its complicated

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

anybody there who can help me

OpenStudy (anonymous):

pls @dan815

OpenStudy (anonymous):

@kiamousekia

OpenStudy (anonymous):

yay @jim_thompson5910 ur here

OpenStudy (anonymous):

and @dan815

jimthompson5910 (jim_thompson5910):

which one are you stuck on?

OpenStudy (anonymous):

i need help on 13-15, 17, 21, 25, 26, 27:b, 28, 34, 35, 36, 37, 38, 39:a,b, 40. i know its a lot pls forgive me

OpenStudy (anonymous):

nvr mind i dont need help on 28

OpenStudy (anonymous):

@jim_thompson5910 , @dan815 r u there

jimthompson5910 (jim_thompson5910):

well there are a lot of similar problems, so why not do it where we help with a few and you practice on the rest?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

lets start with 13-15

OpenStudy (dan815):

okay so lets saw for a member for 1 year he just pays 35 a NON-member will pay lets say 5 dollars every time he uses the gym let n the number of uses lets see at what number of uses the member = non member 35=5*n when n=7, 5*7=35 so a non member if he uses the gym 7 times he will pay the same as a guy who payed for a whole year, if he uses the gym more than 7 times he will have to pay more than the guy with a membership, if he uses the gym less than 7 times he will have to pay less Now for your question instead of 5 dollars every time he uses, they have a different number or some random number k

jimthompson5910 (jim_thompson5910):

I'm stumped. It seems like there's information missing in #13. How much does it cost per visit? It doesn't say.

jimthompson5910 (jim_thompson5910):

is the problem cut off or something?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

@dan815 where did you get those values from?

OpenStudy (anonymous):

it says that the cost of being a member of the frequent visitor program = the cost of not being a member

OpenStudy (dan815):

just made it up for an example, instead of 5 i think ninja has to use a variable there

OpenStudy (anonymous):

the variable is n

OpenStudy (anonymous):

which is the number of visits per year

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

he left

jimthompson5910 (jim_thompson5910):

well I still think there's missing info, but anyway, let's say the cost per day is k dollars. The k is some unknown number if you visit n times for that year, then it costs k*n dollars

OpenStudy (anonymous):

@_

jimthompson5910 (jim_thompson5910):

set that equal to the 5 dollar yearly fee to get k*n = 5

jimthompson5910 (jim_thompson5910):

make sense?

OpenStudy (anonymous):

so thats the equation for 13, right?

jimthompson5910 (jim_thompson5910):

do you see how I formed it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what about 14 and 15

jimthompson5910 (jim_thompson5910):

I think they want you to solve for n

jimthompson5910 (jim_thompson5910):

in #14

OpenStudy (anonymous):

oh let me try

OpenStudy (anonymous):

is it 5?

jimthompson5910 (jim_thompson5910):

get n all by itself in the equation `k*n = 5`

OpenStudy (anonymous):

oh let me try it that way

OpenStudy (anonymous):

how do u divide 5 by k

OpenStudy (anonymous):

nvr mind how do u get n by itself

jimthompson5910 (jim_thompson5910):

you just leave it like that, so you'd have \[\Large n = \frac{5}{k}\]

jimthompson5910 (jim_thompson5910):

that's what you'd have after dividing both sides by k

OpenStudy (anonymous):

and then

jimthompson5910 (jim_thompson5910):

if you knew the value of k (the number it represents), then you could replace k with that number and divide

jimthompson5910 (jim_thompson5910):

but we don't know what k is so we leave it like 5/k

OpenStudy (anonymous):

ok so thats #14

OpenStudy (anonymous):

is it?

jimthompson5910 (jim_thompson5910):

yeah

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

#15

OpenStudy (anonymous):

how do u do number 15

OpenStudy (anonymous):

nvrmind i know that

OpenStudy (anonymous):

#17??

jimthompson5910 (jim_thompson5910):

what would be the answer to #15

OpenStudy (anonymous):

actually i dunno could u help me

OpenStudy (anonymous):

u there

jimthompson5910 (jim_thompson5910):

give it a try and tell me what you think

OpenStudy (anonymous):

is it 5 divided by the money.......i dunno!

jimthompson5910 (jim_thompson5910):

what does n represent

OpenStudy (anonymous):

the # of visits??

jimthompson5910 (jim_thompson5910):

yes, so 5/k represents the number of visits (because it's equal to n)

jimthompson5910 (jim_thompson5910):

if k = 1, then 5/k = 5/1 = 5 basically saying if the price per visit is $1, then you'd have to make 5 visits for the two costs to be equal

OpenStudy (anonymous):

ok thank u very much

jimthompson5910 (jim_thompson5910):

no problem

OpenStudy (anonymous):

what about #17

OpenStudy (anonymous):

8x + 5 = 3x + 15 solve for x

OpenStudy (anonymous):

ok

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