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Mathematics 16 Online
zarkam21 (zarkam21):

Help, will medal

zarkam21 (zarkam21):

OpenStudy (welshfella):

add up the last values in each row what do you get/

OpenStudy (welshfella):

That large E like character means the ' sum of all these 10 values'

OpenStudy (welshfella):

this sum is the answer to step 2

OpenStudy (anonymous):

Is this Sigma notation? mind if i stick around?

zarkam21 (zarkam21):

Well for the first row the total is 0. And for the second row is 224

zarkam21 (zarkam21):

@welshfella

zarkam21 (zarkam21):

@welshfella,, are you there?

OpenStudy (anonymous):

@cc_peach

zarkam21 (zarkam21):

Idk where he went, I really need help

OpenStudy (anonymous):

the second row is 224, that's answer for step 2

OpenStudy (anonymous):

\[Standard deviation(S)=\sqrt{\frac{ \sum_{i=1}^{10} (x _{i}-\mu)^2}{ n-1 }}\]=\[\sqrt{\frac{ 224 }{ 10-1 }}\]

zarkam21 (zarkam21):

So for step 3, it is 224 divided by 9?

OpenStudy (welshfella):

= sqrt((24.89)

OpenStudy (welshfella):

- sorry i got called away

OpenStudy (anonymous):

no, it's \[\sqrt{\frac{ 224 }{ 9 }}\]

zarkam21 (zarkam21):

So 24.89

OpenStudy (welshfella):

divide 224 by 9 first . Then take the square root

zarkam21 (zarkam21):

For step 3 ,,, 24.89

OpenStudy (welshfella):

the standard deviation = sqrt (24.89)

zarkam21 (zarkam21):

Okay so for step three the answer is sqrt 24.89

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

so grab your calculator and evaluate it

zarkam21 (zarkam21):

4.99

OpenStudy (welshfella):

yea

zarkam21 (zarkam21):

Is that all?

zarkam21 (zarkam21):

Thank you

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