Mathematics
16 Online
zarkam21 (zarkam21):
Help, will medal
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zarkam21 (zarkam21):
OpenStudy (welshfella):
add up the last values in each row
what do you get/
OpenStudy (welshfella):
That large E like character means the ' sum of all these 10 values'
OpenStudy (welshfella):
this sum is the answer to step 2
OpenStudy (anonymous):
Is this Sigma notation? mind if i stick around?
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zarkam21 (zarkam21):
Well for the first row the total is 0. And for the second row is 224
zarkam21 (zarkam21):
@welshfella
zarkam21 (zarkam21):
@welshfella,, are you there?
OpenStudy (anonymous):
@cc_peach
zarkam21 (zarkam21):
Idk where he went, I really need help
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OpenStudy (anonymous):
the second row is 224, that's answer for step 2
OpenStudy (anonymous):
\[Standard deviation(S)=\sqrt{\frac{ \sum_{i=1}^{10} (x _{i}-\mu)^2}{ n-1 }}\]=\[\sqrt{\frac{ 224 }{ 10-1 }}\]
zarkam21 (zarkam21):
So for step 3, it is 224 divided by 9?
OpenStudy (welshfella):
= sqrt((24.89)
OpenStudy (welshfella):
- sorry i got called away
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OpenStudy (anonymous):
no, it's \[\sqrt{\frac{ 224 }{ 9 }}\]
zarkam21 (zarkam21):
So 24.89
OpenStudy (welshfella):
divide 224 by 9 first .
Then take the square root
zarkam21 (zarkam21):
For step 3 ,,, 24.89
OpenStudy (welshfella):
the standard deviation = sqrt (24.89)
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zarkam21 (zarkam21):
Okay so for step three the answer is sqrt 24.89
OpenStudy (welshfella):
yes
OpenStudy (welshfella):
so grab your calculator and evaluate it
zarkam21 (zarkam21):
4.99
OpenStudy (welshfella):
yea
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zarkam21 (zarkam21):
Is that all?
zarkam21 (zarkam21):
Thank you