Question

Help!!! Scientific Notation. Document below

Answer 1

I need help with A B C and D

Answer 2

@Michele_Laino

Answer 3

@MikeyMaximum @Nnesha @phi

Answer 4

question #1 we need to compute the distance Venus-Earth

Answer 5

ok

Answer 6

108,000,000 and 150,000,000

Answer 7

from your table, we can write this:
\[\Large d = 150 \cdot {10^6} - 108 \cdot {10^6} = \left( {150 - 108} \right) \cdot {10^6} = ...?\]

Answer 8

32 x 1,000,000

Answer 9

so then 32,000,000 is the difference/what they have to travel from venus to earth?

Answer 10

42, not 32

Answer 11

better is:
\[\Large \begin{gathered}
d = 150 \cdot {10^6} - 108 \cdot {10^6} = \left( {150 - 108} \right) \cdot {10^6} = \hfill \\
= 42 \cdot {10^6} = 4.2 \cdot {10^7} \hfill \\
\end{gathered} \]

Answer 12

oh ok

Answer 13

so then I have to keep on going until jupiter and then add all of them together right?

Answer 14

question B we have to compute the sum of the distance of Mercury, Venus and Earth, first. Such sum is:
\[\large d = 57 \cdot {10^6} + 108 \cdot {10^6} + 150 \cdot {10^6} = \left( {57 + 108 + 150} \right) \cdot {10^6} = ...?\]

Answer 15

\[d = 57 \cdot {10^6} + 108 \cdot {10^6} + 150 \cdot {10^6} = \left( {57 + 108 + 150} \right) \cdot {10^6} = ...?\]

Answer 16

315 x 10^6?

Answer 17

correct!
second we have to compare that distance with the distance of Neptune, which is:
\[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6}\]

Answer 18

? whats d^1??

Answer 19

d1 is the distance of Neptune from the Sun
Is the distance of Neptune from the Sun greater or less than the sum of distances above?

Answer 20

greater?

Answer 21

correct since:
\[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6} > 42 \cdot {10^6}\]

Answer 22

ohh

Answer 23

can you type that in the document please and then send it to me through here??

Answer 24

for b? please

Answer 25

oops.. since :
\[\Large {d_1} = 4.5 \cdot {10^9} = 4500 \cdot {10^6} > 315 \cdot {10^6}\]
sorry for my typo

Answer 26

its all right :D

Answer 27

now, let's go to question C)

Answer 28

lol ok

Answer 29

if I multiply the distance of the Earth from the Sun, by 10, I get this new distance:
\[\Large L = 150 \cdot {10^6} \cdot 10 = 150 \cdot {10^7}\]

Answer 30

ok

Answer 31

and that distance is very close to the distance of Saturn which is:
\[\Large {L_1} = 1.43 \cdot {10^9} = 143 \cdot {10^7}\]
am I right?

Answer 32

i think so

Answer 33

so what is the right name of planet?

Answer 34

saturn

Answer 35

right?

Answer 36

correct!

Answer 37

now, let's go on question D)

Answer 38

haha ok

Answer 39

first, we have to compute the distance Saturn-Earth, which is:
\[\Large D = 1430 \cdot {10^6} - 150 \cdot {10^6} = ...?\]

Answer 40

1280 x 10^6?

Answer 41

correct!
now the requested time is:
time=distance over speed and the speed of Shuttle is:
\[\Large v = 28000 = 28 \cdot {10^3}{\text{Km/h}}\]
so the requested time is:
\[\Large t = \frac{{{\text{distance}}}}{{{\text{speed}}}} = \frac{{1280 \cdot {{10}^6}}}{{28 \cdot {{10}^3}}} = \frac{{1280}}{{28}}{10^{6 - 3}} = ...hours\]

Answer 42

45.71 x 10^3?

Answer 43

that's right!

Answer 44

so thats it?

Answer 45

yes!

Answer 46

thanks!! i just have a question... could you help solve the rest of part a??

Answer 47

yes! sure!

Answer 48

ok i just have trouble calculating the distances in scientific notation.. showing my work

Answer 49

we need to know the distance Venus-Jupiter, which is:
\[\Large d = 779 \cdot {10^6} - 108 \cdot {10^6} = \left( {779 - 108} \right) \cdot {10^6} = ...?\]

Answer 50

yea we already did the one from venus to earth so now i guess we have to calculate from earth to mars

Answer 51

sorry are you asking for question A) right?

Answer 52

yes

Answer 53

ok! then we have to compute the distance Venus-Jupiter

Answer 54

yea

Answer 55

and such distance is:
\[\Large d = 779 \cdot {10^6} - 108 \cdot {10^6} = \left( {779 - 108} \right) \cdot {10^6} = ...?\]

Answer 56

671 x 10^6?

Answer 57

yes! correct! :)

Answer 58

is that all?

Answer 59

yes! we have finished!

Answer 60

wow! yay thanks!! :D

Answer 61

:) :)