Check my answer..
Solve the absolute value inequality. {4x+4/2} <4 {} absolute value I got x> -3 and x<1 (-infinity sign, -3) u (1,infinity sign)
Thats not right.. The 2 is under 4x+2 not just 2
Okay I didn't get that... I will do it again.
I need another one checked.. Use graph to find the set. (-infinity sign,-2) n {-5,4) I have (-infinity sign,4) but I feel like its wrong.
\[\large \frac{ 4x + 4 }{ 2 } < 4 => 2x + 2 < 4\] \[\large 2x + 2 -2 = 4-2 \] \[\large 2x = 2 \] \[\large x = 1\]
Sorry x < 1
It has to have two answers...
I don't know the second one.. sorry .
Uh okay..
@IrishBoy123
is it this? \[\large \left |\frac{ 4x + 4 }{ 2 } \right|< 4\]
Yes
*I got x> -3 and x<1* you're right then
Okay thank you.. What about the other one??
you mean this? Use graph to find the set. (-infinity sign,-2) n {-5,4)
Yes
the actual notation matters a lot with this stuff so i am going to have to guess that the first set includes everything from \(\infty\) to -2, and the second contains everything from -5 to 4 and you have to find the intersection which would be from -5 to -2 you do need to be careful with notation though, eg are these real numbers, integers etc?
I thought it might be that (- 5,-2) but my other example did it different.. (-infinity sign,-3) u [-6,1] Answer--- (-infinity sign,1)
Is this because one problem has the u and the other has n ??
Thank you..
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