find the x intercepts of f(x)=((x^2)+2x-24)/((x^2)+8x+12)
\[f(x)=\frac{ x ^{2}+2x-24 }{ x ^{2}+8x+12 }\]
I have already found x=-6 and x=4, but that was somehow wrong. Is one of these invalid for some reason?
the x = 4 is correct, the other x intercept however is x = 0 :)
@plohrb why isn't x=-6 correct?
you must have made a mistake somewhere, all you do is sub 0 for y and solve
im trying to find out where you could have
guess what i guess you factored ot the quadratic equations right ? we have to find two numbers when we multiply them we should get `product of AC`(a = leading coefficient , c= constant term) when we add or subtract them we should get the middle term
I set the numerator equal to 0, is that wrong?
-6 times 4 = 24 \(\checkmark\) -6+4 isn't positive 2
youre supposed to set the y equal to 0, not the numerator
x-intercepts a point where graph intersect x-axis when y = 0 so substitute y for 0 find factors of the numerator and denominator
if you set y equal to 0 then the denominator ends up getting multiplied by 0 anyways so its the same thing as setting the numerator to 0
if you multiply denominator by 0 then answer would be undefined anything times 0 would be 0 and you can't divide by 0
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