Question

Someone Please HELP ASAP

Answer 1

Yes

Answer 2

Ok i am suppose to convert this into standard form
\[y-4=\frac{ 1 }{ 4 }(x+5)\]

and i did the distribute and got

\[y-4=\frac{ 1 }{ 4 }x+\frac{ 5 }{ 4 }\]

Answer 3

Then i multiply 4 on both sides\[4(y-4)=4y-16\]

\[4y-16=x+\frac{ 5 }{ 4 }\]

then i know u add 16 but i cant put it into standard form from here.... It cant

@Ashleyisakitty @satellite73

Answer 4

@freckles @mathmate @pooja195

Please help

Answer 5

\[y-4=\frac{ 1 }{ 4 }(x+5)\] do not multiply out, multiply by 4 \[4y-16=x+5\]

Answer 6

then put the variables on one side of the equal sign \[x-4y=21\]

Answer 7

oops that is wrong

Answer 8

\[x-4y=-21\] is better

Answer 9

\[\frac{ 1 }{ 4 }*5=\frac{ 5 }{ 4 }\]

Answer 10

@satellite73

Answer 11

@Luigi0210 @mathmate

Answer 12

Please help

Answer 13

@satellite73 has already given the corrected answer as
x−4y=−21
You can work with that.

Answer 14

i dont need the answer

how did he get it.... look at my steps so see where i went wrong Pleaseeee

Answer 15

ok, I'll do it in more detail.

Answer 16

\(y-4=\frac{ 1 }{ 4 }(x+5)\)
Cross multiply
\(4(y-4)=x+5\)
The standard form requires that all coefficients are integers, which we now satisfy.
It is also preferable to express it with Ax+By=C, and A preferably positive.
So we move all variables to the right (where x is positive)
4y-16=x+5
-16-5=x-4y
-21=x-4y
Without loss of generality, we switch sides,
x-4y=-21, same as what @satellite73 got.

Answer 17

oh u didnt distribute the x and 1/4

Answer 18

@mathmate

Answer 19

By cross-multiplying, I distribute on the left hand side 4(y-4) becomes 4y-16

Answer 20

OMG U MADE IT WAY MORE CLEARRRRR

THANKS ALOT

Answer 21

You're welcome! :)