Question

How do I create a table of values to determine the behavior of a graph at the vertical asymptotes?

Answer 1

@mathmate

Answer 2

@Shalante

Answer 3

Can be done by using limits.

Since DNE at x=(VA), use numbers very close to each side of the VA. Hope that helps a little?

Answer 4

the v. asymptote is at x=-1 and the function is \(f(x)=\frac{2x-3}{x+1}\)

Answer 5

Plug and chug values close to the asymptotes
You never took calculus right?

Answer 6

right @Shalante

Answer 7

Yea that is basically it. x=-1 is undefined. Plug like -1.0001 and -1.01 and -0.999& -0.98
Understood?

Answer 8

Oh dang, got to go now.

Answer 9

okay..okay. I'll do that. then it says to use limit notation to explain the behavior. I know what limit notation is...but I don't know the behavior

Answer 10

dang, ok. thanks for your help

Answer 11

Just plug values to the left and right of the equation.
It should tell you.

Answer 12

ok

Answer 13

The reason you need to plot is to see if it goes + or - infinity, from the left or from the right.

Answer 14

And you're expected to identify the value of x where the vertical asymptote occurs.
This you can do by checking at what point the denominator vanishes.

Answer 15

okay. I made my table and now I need to use limit notation to express the behavior.

Answer 16

and I understand that part @mathmate

Answer 17

and I already got the horizontal asymptote.. it's y=2. Now all I need is that one part

Answer 18

Yes, horizontal asymptote is 2, from Lim 2x/x.
(even though this particular question did not ask for it).

Answer 19

actually it did XD I just didn't write it

Answer 20

OOOH I THINK I KNOW WHAT IT MEANS. do I write it in limit notation as it approaches the v. asymptote?

Answer 21

I got it. I only have one more c: I'll open a new question and tag you

Answer 22

ok!