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Mathematics 17 Online
OpenStudy (bloomlocke367):

sketch a graph of function f that satisfies these conditions

OpenStudy (mathmate):

.

OpenStudy (bloomlocke367):

\[\lim_{x \rightarrow 2} f(x)=-3\] \[\lim_{x \rightarrow -3^-} f(x)=f(2)=5\] f is increasing on (-inf, -3) \[\lim_{x \rightarrow -3^-}f(x)>\lim_{x \rightarrow -3^+}f(x)\] f is constant on (x, +inf)

OpenStudy (bloomlocke367):

it has to satisfy all of those D:

OpenStudy (mathmate):

Can you check the following? f is constant on (x, +inf)

OpenStudy (bloomlocke367):

Yes I got that. ^.^

OpenStudy (bloomlocke367):

it's an open circle on (2,2) right?

OpenStudy (mathmate):

is it "f(x) is constant on (2,+inf)?

OpenStudy (bloomlocke367):

no, it just says f. I'm pretty sure f and f(x) mean the same thing, right?

OpenStudy (mathmate):

but is "f is constant on (2,+inf)"? (i.e. not (x,+inf) )

OpenStudy (bloomlocke367):

yes

OpenStudy (bloomlocke367):

I have, right now, an open circle on point (2,2) with a horizontal line going to the right c: that's right, right?

OpenStudy (mathmate):

or is it "f is constant on (-3,+inf)"?

OpenStudy (bloomlocke367):

f is constant on (2, +inf)

OpenStudy (mathmate):

Well, we have Lim f(x) x->2 = -3, so the horizontal line should be at y=-3. |dw:1441333851902:dw| agree?

OpenStudy (bloomlocke367):

wait... why -3?

OpenStudy (bloomlocke367):

wait....nvm. I see now

OpenStudy (mathmate):

From the first condition, \(Lim_{x->2} ~~f(x)=-3\)

OpenStudy (mathmate):

so far so good?

OpenStudy (mathmate):

from f(2)=5 (in the second line), we have |dw:1441334065831:dw|

OpenStudy (mathmate):

ok there?

OpenStudy (bloomlocke367):

is that vertical line supposed to be there?

OpenStudy (mathmate):

The rest of line 2 (lim x->3- = 5 ) gives: |dw:1441334208871:dw| then from the fourth line f is increasing up to x=-3

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