Mathematics
8 Online
OpenStudy (tootsi123):
Which of the following is polynomial factor of 8x^2+22x-6?
A (4x-3)
B (4x+3)
C (8x-2)
D (8x+3)
E (8x+6)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tootsi123):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what is the GCF of 8,22, and 6 ?
OpenStudy (tootsi123):
Oh wait i think i get it hold on...
8= 2^3
22=2*11
6=2*3
OpenStudy (tootsi123):
is that right so far??
jimthompson5910 (jim_thompson5910):
notice how 2 is a factor in each, so we can factor out 2
8x^2+22x-6 = 2(4x^2+11x - 3)
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
how would we factor 4x^2+11x - 3 ?
OpenStudy (tootsi123):
Wouldn't you start simplifying the problem?
jimthompson5910 (jim_thompson5910):
multiply the first coefficient (4) and the last term (-3)
4*(-3) = -12
what two factors of -12 add to 11 ?
jimthompson5910 (jim_thompson5910):
put another way:
what two numbers multiply to -12 and add to 11?
OpenStudy (tootsi123):
Wait i am confused... i thought you couldn't combine terms unless they were like terms.... and would 3 be one
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
I'm not combining like terms
jimthompson5910 (jim_thompson5910):
I'm asking for the two numbers because it will help factor
OpenStudy (tootsi123):
oh. Okay so 11 is a prime number so its only factor is one.
OpenStudy (tootsi123):
-12 could be 6,2,3,4
jimthompson5910 (jim_thompson5910):
here are all of the ways to multiply two whole numbers to get -12
-1*12
-2*6
-3*4
-4*3
-6*2
-12*1
which pair of factors will add up to 11?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tootsi123):
The first one
jimthompson5910 (jim_thompson5910):
yep
-1*12 = -12
-1 + 12 = 11
jimthompson5910 (jim_thompson5910):
so we can break up the 11x into -1x + 12x
OpenStudy (tootsi123):
Oh okay...
jimthompson5910 (jim_thompson5910):
4x^2+11x - 3
4x^2-1x + 12x - 3
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
then we'd factor 4x^2-1x + 12x - 3 by grouping
jimthompson5910 (jim_thompson5910):
group up the terms in pairs
4x^2-1x + 12x - 3
(4x^2-1x) + (12x - 3)
do you see what step is next?
OpenStudy (tootsi123):
Simplify them.
jimthompson5910 (jim_thompson5910):
specifically you factor each group
jimthompson5910 (jim_thompson5910):
how can you factor 4x^2-1x ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (tootsi123):
I don't know?
jimthompson5910 (jim_thompson5910):
we can factor out x, agreed?
4x^2 - 1x = x(4x - 1)
OpenStudy (tootsi123):
oh yeah since they are like terms
jimthompson5910 (jim_thompson5910):
how would you factor 12x - 3 ?
OpenStudy (tootsi123):
Wouldn't you just do 12 -3 and then add the x
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
what factors do 12 and 3 have in common?
jimthompson5910 (jim_thompson5910):
12x and -3 aren't like terms
OpenStudy (tootsi123):
oh duh 3
jimthompson5910 (jim_thompson5910):
yeah so 12x - 3 = 3(4x - 1)
jimthompson5910 (jim_thompson5910):
4x^2-1x + 12x - 3
(4x^2-1x) + (12x - 3)
x(4x - 1) + 3(4x - 1)
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
what factor shows up twice?
OpenStudy (tootsi123):
one
jimthompson5910 (jim_thompson5910):
what else
OpenStudy (tootsi123):
4
jimthompson5910 (jim_thompson5910):
the 4x-1 shows up twice
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
we can factor that out
x(4x - 1) + 3(4x - 1)
will turn into
(x+3)(4x - 1)
jimthompson5910 (jim_thompson5910):
so hopefully you see how 8x^2+22x-6 factors to 2(x+3)(4x - 1)
OpenStudy (tootsi123):
I think so
jimthompson5910 (jim_thompson5910):
go over the steps a few times to make sure you have a solid grasp of it. you can ask questions if you aren't sure about a step or two
OpenStudy (tootsi123):
Okay