An electron is moving at $\sf 10^6$ m/s in a direction parallel to a current of 5A flowing through an infinite long straight wire separated by a perpendicular distance of 0.1 m in air. Magnetic force experienced by the electron will be?

Question

abhisar · Answer

This is how I am doing....

The field due to the infinite current wire at any point at a perpendicular distance of 0.1m from it can be calculated by ampere's law as,

$\sf B=\Large \frac{5 \times 2\mu_0}{4\pi\times 0.1}=10^2\times 10^{-7}=10^{-5}$

Now, magnetic force can be calculated as,

$\sf \vec{F_m}=q(\vec{V}\times \vec{B})\ \Rightarrow 1.6\times 10^{-19}(10^6\times 10^{-5}\times sin(90^0))=1.6 \times 10^{-18}$

rushwr · Answer

Ur methods are correct I suppose ! Still having a slight doubt on the 1st part . Applying of F=BqV is alright. What's the answer given ?

abhisar · Answer

Answer is different doe, the key says $\sf 4 \times 10^{-11}$ N :(

abhisar · Answer

Whoops... Wait !!

The answer is $\sf 1.6 \times 10^{-18}$N. All this time I was looking answer for different question :D.

rushwr · Answer

lol

rushwr · Answer

ok then

abhisar · Answer

Thnx doe c:

rushwr · Answer

lol no problem