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Physics 15 Online
OpenStudy (anonymous):

Why would Fx and Fy = 0 when you're moving an object at a constant velocity? Problem: 14kg mower being pushed at a 45degree angle from above with a force of 88N, mg=137.2, A) Find Ff B) Find Fn

OpenStudy (photon336):

For your first question we need to go into the nuts and bolts of the formula itself \[F = ma \] this formula tells us that a force is equal to the product of the mass times the acceleration. Sometimes we have multiple forces and in multiple directions too. so we need to do the following. dont be to imitated by these formulas all they say is that in the X direction you add up all the forces in the x direction to find the net force in the X direction. Same for the Y. We do this because force is a vector it has both magnitude a value and a direction. these forces to my knowledge are independent of one another. \[F _{nety} = F _{y}1 +F _{y2}... \] \[F _{netx} = F_{x1} +F_{x2}... n \]

OpenStudy (photon336):

|dw:1441390450698:dw| once you find both Fnet X and Fnet Y you can imagine that it would look something like a right triangle so to find the magnitude total force. you take the values for Fnetx and F net Y and do the following similar to this equation \[a ^{2} + b ^{2} = c ^{2} \] \[Fnet = \sqrt{ (fnetx)^{2}+(Fnety)^{2}}\]

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